回忆四则运算堆栈
四则运算用到了堆栈的原理,计算机更喜欢先字符后运算符号的方法,也就是2+3变成23+
运用堆栈可以很好的实现这种方法
import java.util.ArrayList; import java.util.Stack; public class Stack2 { public static double getResult(String n,double num1,double num2) { double result = 0; switch (n) { case "+": result = num1+num2; break; case "-": result = num1-num2; break; case "*": result = num1*num2; break; case "/": result = num1/num2; break; default: break; } return result; } public int priority(String oper){ if(oper.contentEquals("*")||oper.contentEquals("/")){ return 1; }else if (oper.contentEquals("+")||oper.contentEquals("-")) { return 0; } else { return -1; // 假定目前的表达式只有 +, - , * , / } } public ArrayList<String> getArraylist(String n){ String str = ""; int j=0; ArrayList<String> list = new ArrayList<String>(); for(char a:n.toCharArray()) { if(Character.isDigit(a)) { str += a; } else { if(str.contentEquals("")) { list.add(a+""); } else { list.add(str); list.add(a+""); } str = ""; j= n.lastIndexOf(a); } } list.add(n.substring(j+1)); return list; } public double getAnswer(ArrayList<String> list) { Stack<String> stack1 = new Stack<String>(); Stack<String> stack2 = new Stack<String>(); double num1; double num2; int index = 0; while(true) { String a2 = list.get(index); char ch[] = a2.toCharArray(); if(Character.isDigit(ch[0])) { stack2.push(a2); } else { if(stack1.isEmpty()) { stack1.push(a2); } else { if(a2.contentEquals("(")){ stack1.push(a2); } else if(a2.contentEquals(")")){ num1 = Double.parseDouble(stack2.pop()); num2 = Double.parseDouble(stack2.pop()); stack2.push(""+getResult(stack1.pop(),num2,num1)); stack1.pop(); } else { if(priority(a2)<=priority(stack1.peek())) { num1 = Double.parseDouble(stack2.pop()); num2 = Double.parseDouble(stack2.pop()); stack2.push(""+getResult(stack1.pop(),num2,num1)); } else { stack1.push(a2); } } } } index++; if(index-1==stack1.size()){ break; } } while(true) { if(stack1.isEmpty()){ //当我们的符号栈为空的时候则计算到最后的结果,数栈中只有一个结果那就是我们的结果 break; } num1 = Double.parseDouble(stack2.pop()); num2 = Double.parseDouble(stack2.pop()); stack2.push(""+getResult(stack1.pop(),num2,num1)); } return Integer.parseInt(stack2.peek()); } public static void main(String[] args) { Stack2 stack = new Stack2(); String a = "36+4*3+2/2"; double b = stack.getAnswer(stack.getArraylist(a)); System.out.print(b); } }