uva12534 Binary Matrix 2(最小费用最大流)
http://blog.csdn.net/qq564690377/article/details/17082055
做的时候觉得明显是费用流,但是真的不知道怎么建图,看了上面的博客会稍微清晰一点。后面再补一点细节吧,然后发现这道题用自己平时的费用流模板是水不过去的,所以找了份别人AC的代码弄了个zkw最小费用流的模板上来,算是存下模板吧。
补充点个人的理解吧,个人的网络流做的题还是太少了,所以想不到怎么建模,其实感觉上还是比较直接的一个行列二分图建模。首先就是枚举最后有多少个1剩下来,假设当前的已经有cur个1了,然后我要达到tot,那么每一行应该有tot/n个,每一列应该有tot/m个,所以我们可以对每行建一个点,对每列建一个点,从源点到行的点限流tot/n,列的点到汇点限流tot/m,这样的话当满流的时候其实就能保证每一行的1相等,每一列的1也相等。然后建边的时候就是每个处于(i,j)的点和i行j列的点连一条边,假设原本是1就费用为0,原本是0就费用为1.那么按照这样跑一遍费用流,费用x就是图里面需要由0变成1的点的个数,我们只需要再求出y,即图里由1变成0的个数就可以了。那么y等于多少呢? 不难发现图中多出来的1应该满足 x-y=tot-cur 所以y=x+cur-tot 所以最后的费用是x+y=2*x+cur-tot。
http://blog.sina.com.cn/s/blog_61034ad90100gwdw.html
上面的博客研究了spfa的网络流和zkw的网络流,可能zkw网络流会比较适用在二分图,稠密图上吧。
#pragma warning(disable:4996) #include <iostream> #include <cstring> #include <string> #include <vector> #include <cmath> #include <algorithm> #include <cstdio> #include <queue> using namespace std; #define ll long long #define eps 1e-8 #define maxn 100 #define maxe 4000 #define inf 0x3f3f3f3f using namespace std; char b[50][50]; int n, m; /*int siz; struct Edge{ int u, v, nxt, cap, cost; }edge[maxe]; int head[maxn]; struct MinCostMaxFlow { queue<int> que; int add; // edges number int vn; // total vertex number int cost[maxn], in[maxn], pre[maxn]; bool vis[maxn]; void init(){ add = 0; vn = siz + 10; memset(head, -1, sizeof(head)); while (!que.empty()) que.pop(); } void insert(int u, int v, int w, int c){ edge[add].u = u; edge[add].v = v; edge[add].cap = w; edge[add].cost = c; edge[add].nxt = head[u]; head[u] = add++; edge[add].u = v; edge[add].v = u; edge[add].cap = 0; edge[add].cost = -c; edge[add].nxt = head[v]; head[v] = add++; } bool spfa(int s, int e){ memset(cost, 0x3f3f3f3f, sizeof(cost)); memset(in, 0, sizeof(in)); memset(vis, 0, sizeof(vis)); cost[s] = 0; pre[s] = -1; que.push(s); vis[s] = true; in[s]++; while (!que.empty()){ int u = que.front(); que.pop(); vis[u] = false; for (int i = head[u]; i != -1; i = edge[i].nxt){ int v = edge[i].v; if (edge[i].cap > 0 && cost[v] > cost[u] + edge[i].cost){ cost[v] = cost[u] + edge[i].cost; pre[v] = i; if (!vis[v]){ que.push(v); vis[v] = true; in[v]++; if (in[v] > vn) return false; } } } } if (cost[e] < inf) return true; else return false; } int mincostmaxflow(int s, int e){ int mincost = 0, maxflow = 0; while (spfa(s, e)){ int flow = inf; for (int i = pre[e]; i != -1; i = pre[edge[i].u]){ flow = min(flow, edge[i].cap); } maxflow += flow; for (int i = pre[e]; i != -1; i = pre[edge[i].u]){ edge[i].cap -= flow; edge[i ^ 1].cap += flow; } mincost += cost[e] * flow; } return mincost; } }net; */ struct Edge { int u, v, cap, cost, nxt; Edge(int _u, int _v, int _cap, int _cost, int _nxt) : u(_u), v(_v), cap(_cap), cost(_cost), nxt(_nxt){} Edge(){}; }edge[maxe]; int head[maxn]; struct ZKW_MinCostMaxFlow { int add; int cur[maxn]; int dis[maxn]; bool inq[maxn]; queue<int> q; bool vis[maxn]; int ss, tt, n; int min_cost, max_flow; void init() { memset(head, -1, sizeof(head)); add = 0; } void insert(int u, int v, int cp, int ct) { edge[add] = Edge(u, v, cp, ct, head[u]); head[u] = add++; edge[add] = Edge(v, u, 0, -ct, head[v]); head[v] = add++; } int aug(int u, int flow) { if (u == tt) return flow; vis[u] = true; for (int i = cur[u]; i != -1; i = edge[i].nxt) { int v = edge[i].v; if (edge[i].cap && !vis[v] && dis[u] == dis[v] + edge[i].cost) { int tmp = aug(v, min(flow, edge[i].cap)); edge[i].cap -= tmp; edge[i ^ 1].cap += tmp; cur[u] = i; if (tmp) return tmp; } } return 0; } bool modify_label() { int d = inf; for (int u = 0; u < n; u++) if (vis[u]) for (int i = head[u]; i != -1; i = edge[i].nxt) { int v = edge[i].v; if (edge[i].cap && !vis[v]) d = min(d, dis[v] + edge[i].cost - dis[u]); } if (d == inf) return false; for (int i = 0; i < n; ++i) if (vis[i]) { vis[i] = false; dis[i] += d; } return true; } pair<int, int> mincostmaxflow(int s, int t, int _n) { ss = s, tt = t, n = _n; min_cost = max_flow = 0; for (int i = 0; i < n; i++) dis[i] = 0; while (true) { for (int i = 0; i < n; i++) cur[i] = head[i]; while (true) { for (int i = 0; i < n; i++) vis[i] = 0; int tmp = aug(s, inf); if (tmp == 0) break; max_flow += tmp; min_cost += tmp * dis[ss]; } if (!modify_label()) break; } return make_pair(min_cost, max_flow); } }net; int main() { int T; cin >> T; int ca = 0; while (T--){ scanf("%d%d", &n, &m); for (int i = 0; i < n; i++) scanf("%s", b[i]); int tot = 0; for (int i = 0; i < n; ++i){ for (int j = 0; j < m; ++j){ if (b[i][j] == '1') tot++; } } int ans = min(n*m - tot, tot); for (int i = 1; i <= n*m; ++i){ if (i%n != 0 || i%m != 0) continue; if (abs(tot - i) >= ans) continue; net.init(); int src = n + m, sink = src + 1; for (int k = 0; k < n; ++k){ net.insert(src, k, i / n, 0); } for (int k = n; k < n + m; k++){ net.insert(k, sink, i / m, 0); } for (int x = 0; x < n; x++){ for (int j = 0; j < m; j++){ if (b[x][j] == '1') net.insert(x, j + n, 1, 0); else net.insert(x, j + n, 1, 1); } } ans = min(ans, net.mincostmaxflow(src, sink,sink+1).first * 2 + tot - i); } printf("Case %d: %d\n", ++ca, ans); } return 0; }