摘要： 原题链接#include int main(){ int t, n, m,a ,b; scanf("%d", &t); while(t--){ scanf("%d%d", &n, &m); a = (m - 2 * n) / 2; //rabbit b = n - a; if(a < 0 || b < 0 || m & 1) printf("No answer\n"); else printf("%d %d\n", b, a); } return 0;} 阅读全文