[LeetCode] Count and Say
The count-and-say sequence is the sequence of integers beginning as follows:1, 11, 21, 1211, 111221, ...
1
is read off as "one 1"
or 11
.11
is read off as "two 1s"
or 21
.21
is read off as "one 2
, then one 1"
or 1211
.
Given an integer n, generate the nth sequence.
Note: The sequence of integers will be represented as a string.
string say; string countAndSay(int n) { if(n == 1) return "1"; say = "1"; //return say "n - 1" for(int i = 1;i < n;i++) { string tmp = ""; char cur = say[0]; int count = 1; for(int j = 1;j < say.length();j++) { if(say[j] == cur) { count++; } else { tmp = tmp + char(count + '0') + cur; cur = say[j]; count = 1; } } tmp = tmp + char(count + '0') + cur; say = tmp; } return say; }