判断webservice/url是否有效
添加引用COM:Microsoft XML,V5.0
导入命名空间using MSXML2;
/// <summary> /// 判断webservice是否可用 /// </summary> /// <returns>true:可用;false:不可用</returns> public bool getWSStatus(string url) { XMLHTTP http = new XMLHTTP(); try { http.open("GET", url, false, null, null); http.send(null); int iStatus = http.status; //如果取得的网页状态不正确, 就是不存在或没权访问 if (iStatus == 200) return true; else return false; } catch { return false; } }