C#应用程序随机启动

如果想你写的程序随系统开机一起启动的话，那么你可以照下面这个方法来做。 
RunWhenStart(false, Application.ProductName, Application.StartupPath + @\"\\MUS.exe\"); 
  

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  /// <summary>

  /// 开机启动项

/// </summary>

  /// <param name=\"Started\">是否启动</param>

  /// <param name=\"name\">启动值的名称</param>

  /// <param name=\"path\">启动程序的路径</param>

  public static void RunWhenStart(bool bStarted, string name, string path)

  {

      RegistryKey hklm = Registry.LocalMachine;

      RegistryKey run = hklm.CreateSubKey(@"SOFTWARE\Microsoft\Windows\CurrentVersion\Run\");

      try

      {

          if (bStarted)

          {

              run.SetValue(name, path);

          }

          else

          {

              run.DeleteValue(name);

          }

      }

      catch (Exception err)

      {

          MessageBox.Show(err.Message.ToString(), "系统提示", MessageBoxButtons.OK, MessageBoxIcon.Error);

      }

      finally

      {

          hklm.Close();

          run.Close();

      }

  }

添加一个checkbox在启动时显示于用户界面，并添加CheckedChanged事件，即可以通过checkbox设置是否随时启动。
       

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   /// <summary>

  /// 设置开机自动启动

/// </summary>

  /// <param name="sender"></param>

  /// <param name="e"></param>

  private void chrb_CheckedChanged(object sender, EventArgs e)

  {

      string startPath = Application.ExecutablePath;

 

      RunWhenStart(chrb.Checked, "SendMessage", startPath);

  }