c++ 函数内定义变量返回 static

测试代码：

#include<bits/stdc++.h>
using namespace std;
char * fun() {
    char s[] = "abcde";
    printf("fun:%p\n",s);
    return s;
}
char * fun1() {
    static char s[] = "abcde";
    printf("fun1:%p\n",s);
    return s;
}
char * fun2() {
    char *s = new char[6];
    strcpy(s,"abcde");
    printf("fun2:%p\n",s);
    return s;
}
void fun4() {
    static int a = 0;
    a++;
    printf("%d\n",a);
}
int main() {
    printf("%p %s\n",fun(),fun());
    printf("%p %s\n",fun1(),fun1());
    printf("%p %s\n",fun2(),fun2());
    fun4();
    fun4();
    fun4();
    return 0;
}

 

运行结果：

fun:0x7ffe5d532b00
fun:0x7ffe5d532b00
(nil) (null)
fun1:0x601060
fun1:0x601060
0x601060 abcde
fun2:0x2587030
fun2:0x2587050
0x2587050 abcde
1
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3