bzoj 3190: [JLOI2013]赛车

这个题半平面交很显然了,都直接给出直线了有木有!!??答案就是交出来的(分段函数)凸壳有几块就行。。有相等什么的情况特别恶心。

然而本蒟蒻直接上的模板还是错了。。。跪(不知道为什么)

  1 /*#include<bits/stdc++.h>
  2 #define N 100005
  3 #define LL long long 
  4 #define eps 1e-8
  5 #define double long double
  6 using namespace std;
  7 inline int ra()
  8 {
  9     int x=0,f=1; char ch=getchar();
 10     while (ch<'0' || ch>'9') {if (ch=='-') f=-1; ch=getchar();}
 11     while (ch>='0' && ch<='9') {x=x*10+ch-'0'; ch=getchar();}
 12     return x*f;
 13 }
 14 const double inf=1e15;
 15 int n,cnt,tot,L,R,ans[N],num,orz;
 16 struct data_in{int k,b; int id;}q[N];
 17 struct point{double x,y;};
 18 struct line{
 19     point a,b; double angle; int id;
 20     void print(){
 21         printf("%.1lf   %.1lf   %.1lf   %.1lf\n",a.x,a.y,b.x,b.y);
 22     }
 23 }l[N],s[N];
 24 double operator * (point a, point b){
 25     return a.x*b.y-a.y*b.x;
 26 }
 27 point operator - (point a, point b){
 28     point t; t.x=a.x-b.x; t.y=a.y-b.y; return t;
 29 }
 30 bool operator < (line a, line b){
 31     if (a.angle==b.angle) return (b.b-a.a)*(a.b-a.a)>=0;
 32     return a.angle<b.angle;
 33 }
 34 bool operator == (point a, point b){
 35     return a.x==b.x && a.y==b.y;
 36 }
 37 point intersection(line a, line b)
 38 {
 39     point ans; double k1,k2,t;
 40     k1=(b.a-a.a)*(a.b-a.a);
 41     k2=(a.b-a.a)*(b.b-a.a);
 42     t=k1/(k1+k2);
 43     ans.x=b.a.x+(b.b.x-b.a.x)*t;
 44     ans.y=b.a.y+(b.b.y-b.a.y)*t;
 45     return ans;
 46 }
 47 bool jud(line a, line b, line t)
 48 {
 49     point p=intersection(a,b);
 50 //    printf("%lf  %lf",p.x,p.y);while(1);
 51     return (t.a-p)*(t.b-p)<0;
 52 }
 53 void half_plane_intersection()
 54 {
 55     for (int i=1; i<=cnt; i++)
 56         if ((l[i].angle!=l[i-1].angle) || (l[i].angle==l[i-1].angle && l[i].a==l[i-1].a && l[i].b==l[i-1].b)) l[++tot]=l[i];
 57 //    for (int i=1; i<=tot; i++) l[i].print();
 58     L=1; R=0; s[++R]=l[1]; s[++R]=l[2];
 59 //    cout<<jud(l[1],l[2],l[3]);
 60     for (int i=3; i<=tot; i++)
 61     {
 62         if (l[i].a==l[i-1].a && l[i].b==l[i-1].b) {s[++R]=l[i]; continue;}
 63         while (L<R && jud(s[R],s[R-1],l[i])) R--;
 64         while (L<R && jud(s[L],s[L+1],l[i])) L++;
 65         s[++R]=l[i];
 66     }
 67     while (L<R && jud(s[R],s[R-1],s[L])) R--;
 68     while (L<R && jud(s[L],s[L+1],s[R])) L++;
 69 }
 70 bool cmp(data_in a, data_in b)
 71 {
 72     if (a.k==b.k) return a.b<b.b;
 73     return a.k<b.k;
 74 }
 75 int main()
 76 {
 77     n=ra();
 78     for (int i=1; i<=n; i++) q[i].b=ra();
 79     for (int i=1; i<=n; i++) q[i].k=ra();
 80     for (int i=1; i<=n; i++) q[i].id=i;
 81     sort(q+1,q+n+1,cmp);
 82     for (int i=1; i<=n; i++)
 83         if (q[i].k!=q[i-1].k || (q[i].k==q[i-1].k && q[i].b==q[i-1].b)) q[++orz]=q[i];
 84     for (int i=1; i<=orz; i++)
 85     {
 86         l[++cnt].a.x=0; l[cnt].a.y=q[i].b;
 87         l[cnt].b.x=2; l[cnt].b.y=2*q[i].k+q[i].b;
 88         l[cnt].id=q[i].id;
 89     }
 90     l[++cnt].a.x=-1; l[cnt].a.y=inf; l[cnt].b.x=-1; l[cnt].b.y=-1;
 91     l[++cnt].a.x=-1; l[cnt].a.y=-1; l[cnt].b.x=inf; l[cnt].b.y=-1;
 92     for (int i=1; i<=cnt; i++)
 93         l[i].angle=atan2(l[i].b.y-l[i].a.y,l[i].b.x-l[i].a.x);
 94     sort(l+1,l+cnt+1);
 95     half_plane_intersection();
 96     for (int i=L; i<=R; i++)
 97         if (s[i].id) ans[++num]=s[i].id;
 98     sort(ans+1,ans+num+1);
 99     cout<<num<<endl;
100     for (int i=1; i<=num; i++)
101     {
102         printf("%d",ans[i]);
103         if (i!=num) printf(" ");
104     }
105     return 0;
106 }*/
107 
108 #include<cstdio>
109 #include<algorithm>
110 #define N 100005
111 #define eps 1e-8
112 using namespace std;
113 int n,top;
114 int ans[N];
115 struct line{
116     int k,b,id;
117     friend bool operator < (line a, line b){
118         if (a.k==b.k) return a.b<b.b;
119         return a.k<b.k;
120     }
121     friend double inter(line a, line b){
122         return (double)(a.b-b.b)/(b.k-a.k);
123     }
124 }c[N],q[N];
125 bool jud(line a, line b, line t)
126 {
127     return inter(a,b)>inter(a,t);
128 }
129 int main()
130 {
131     scanf("%d",&n);
132     for (int i=1; i<=n; i++) scanf("%d",&c[i].b);
133     for (int i=1; i<=n; i++) scanf("%d",&c[i].k);
134     for (int i=1; i<=n; i++) c[i].id=i;
135     sort(c+1,c+n+1); top=1;
136     for (int i=2; i<=n; i++)
137     {
138         if (c[i].k!=c[i-1].k || (c[i].k==c[i-1].k && c[i].b==c[i-1].b))
139             top++;
140         c[top]=c[i];
141     }
142     n=top; top=0;
143     q[++top]=c[1]; ans[1]=c[1].id;
144     for (int i=2; i<=n; i++)
145     {
146         while (top>=1 && inter(q[top],c[i])<-eps) top--;
147         while (top>=2 && jud(q[top-1],q[top],c[i])) top--;
148         q[++top]=c[i]; ans[top]=c[i].id;
149     }
150     printf("%d\n",top);
151     sort(ans+1,ans+top+1);
152     for (int i=1; i<=top; i++)
153     {
154         printf("%d",ans[i]);
155         if (i!=top) printf(" ");
156     }
157 //    while (1);
158     return 0;
159 }

 

posted @ 2017-03-02 21:25  ws_ccd  阅读(226)  评论(0编辑  收藏  举报