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杭电ACM1001

原题:http://acm.hdu.edu.cn/showproblem.php?pid=1001

 1 #include <stdio.h>
 2 
 3 int main(void)
 4 {
 5     int i,n,sum;
 6     sum = 0;
 7     while(scanf("%d",&n)!=EOF)
 8     {
 9         sum=0;
10         for (i=0;i<=n;i++)
11             sum+=i;
12         printf("%d\n\n",sum);
13     }
14     return 0;
15 }

 

Sum Problem

Time Limit: 1000/500 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 416900    Accepted Submission(s): 105068


Problem Description
Hey, welcome to HDOJ(Hangzhou Dianzi University Online Judge).

In this problem, your task is to calculate SUM(n) = 1 + 2 + 3 + ... + n.
 

 

Input
The input will consist of a series of integers n, one integer per line.
 

 

Output
For each case, output SUM(n) in one line, followed by a blank line. You may assume the result will be in the range of 32-bit signed integer.
 

 

Sample Input
1 100
 

 

Sample Output
1 5050

posted on 2016-08-09 17:39  czhhbp  阅读(511)  评论(0编辑  收藏  举报