linked-list-cycle-ii (链表判环 并返回交点)

题目描述

Given a linked list, return the node where the cycle begins. If there is no cycle, returnnull.

Follow up:
Can you solve it without using extra space?

/**
 * Definition for singly-linked list.
 * class ListNode {
 *     int val;
 *     ListNode next;
 *     ListNode(int x) {
 *         val = x;
 *         next = null;
 *     }
 * }
 */
public class Solution {
    public ListNode detectCycle(ListNode head) {
        if(head == null || head.next == null) {
            return null;
        }
        ListNode fast = head, slow = head;
        while(fast != null && fast.next != null) {
            fast = fast.next.next;
            slow = slow.next;
            if(fast == slow) {
                break;
            }
        }
        if(fast == null || fast.next == null) {
            return null;
        }
        fast = head;
        while(fast != slow) {
            fast = fast.next;
            slow = slow.next;
        }
        return fast;

    }
}