# 有1、2、3、4个数字,能组成多少个互不相同且无重复数字的三位数?都是多少?def three_number():
ll = [1, 2, 3, 4]
count = 0
for a in ll:
for b in ll:
for c in ll:
if (a != b) and (a != c) and (b != c):
count += 1
print('{}{}{}'.format(a, b, c))
return count
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2020-08-27 17:47焚音留香
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