rust学习-记录第一个完成的rust算法题

给你一个下标从 0 开始的 8 x 8 网格 board ,其中 board[r][c] 表示游戏棋盘上的格子 (r, c) 。棋盘上空格用 '.' 表示,白色格子用 'W' 表示,黑色格子用 'B' 表示。

游戏中每次操作步骤为:选择一个空格子,将它变成你正在执行的颜色(要么白色,要么黑色)。但是,合法 操作必须满足:涂色后这个格子是 好线段的一个端点 (好线段可以是水平的,竖直的或者是对角线)。

好线段 指的是一个包含 三个或者更多格子(包含端点格子)的线段,线段两个端点格子为 同一种颜色 ,且中间剩余格子的颜色都为 另一种颜色 (线段上不能有任何空格子)。你可以在下图找到好线段的例子:

给你两个整数 rMove 和 cMove 以及一个字符 color ,表示你正在执行操作的颜色(白或者黑),如果将格子 (rMove, cMove) 变成颜色 color 后,是一个 合法 操作,那么返回 true ,如果不是合法操作返回 false 。

 

示例 1:

输入:board = [[".",".",".","B",".",".",".","."],[".",".",".","W",".",".",".","."],[".",".",".","W",".",".",".","."],[".",".",".","W",".",".",".","."],["W","B","B",".","W","W","W","B"],[".",".",".","B",".",".",".","."],[".",".",".","B",".",".",".","."],[".",".",".","W",".",".",".","."]], rMove = 4, cMove = 3, color = "B"
输出:true
解释:'.','W' 和 'B' 分别用颜色蓝色,白色和黑色表示。格子 (rMove, cMove) 用 'X' 标记。
以选中格子为端点的两个好线段在上图中用红色矩形标注出来了。

示例 2:

输入:board = [[".",".",".",".",".",".",".","."],[".","B",".",".","W",".",".","."],[".",".","W",".",".",".",".","."],[".",".",".","W","B",".",".","."],[".",".",".",".",".",".",".","."],[".",".",".",".","B","W",".","."],[".",".",".",".",".",".","W","."],[".",".",".",".",".",".",".","B"]], rMove = 4, cMove = 4, color = "W"
输出:false
解释:虽然选中格子涂色后,棋盘上产生了好线段,但选中格子是作为中间格子,没有产生以选中格子为端点的好线段。

 

提示:

  • board.length == board[r].length == 8
  • 0 <= rMove, cMove < 8
  • board[rMove][cMove] == '.'
  • color 要么是 'B' 要么是 'W' 。
impl Solution {
    pub fn check_move(board: Vec<Vec<char>>, r_move: i32, c_move: i32, color: char) -> bool {
        let pArr=[[1,0],[-1,0],[0,1],[0,-1],[1,-1],[1,1],[-1,1],[-1,-1]];
        let mut has=false;
        for [dx,dy] in pArr{
            let mut x=(r_move+dx) as usize;
            let mut y=(c_move+dy) as usize;
            let mut first=true;
            while x<8&&x>=0&&y<8&&y>=0{
                if first{
                    first=false;
                    if board[x][y]=='.'||board[x][y]==color{
                        break;
                    }
                }else{
                    if board[x][y]=='.'{
                        break;
                    }else if board[x][y]==color{
                        has=true;
                        break
                    }
                    x+=dx as usize;
                    y+=dy as usize;
                }
                
            }
        }
        return has;
    }
}

 

posted @ 2024-07-07 13:58  无工时代  阅读(3)  评论(0编辑  收藏  举报