spring jpa data的关键字

这些都是对于方法名的使用,如果自己编写sql可以使用@Query("select ?1 ")编写sql,在进行删除和修改操作时需要@modifying

KeywordSampleJPQL snippet

And

findByLastnameAndFirstname

… where x.lastname = ?1 and x.firstname = ?2

Or

findByLastnameOrFirstname

… where x.lastname = ?1 or x.firstname = ?2

Is,Equals

findByFirstname,findByFirstnameIs,findByFirstnameEquals

… where x.firstname = 1?

Between

findByStartDateBetween

… where x.startDate between 1? and ?2

LessThan

findByAgeLessThan

… where x.age < ?1

LessThanEqual

findByAgeLessThanEqual

… where x.age ⇐ ?1

GreaterThan

findByAgeGreaterThan

… where x.age > ?1

GreaterThanEqual

findByAgeGreaterThanEqual

… where x.age >= ?1

After

findByStartDateAfter

… where x.startDate > ?1

Before

findByStartDateBefore

… where x.startDate < ?1

IsNull

findByAgeIsNull

… where x.age is null

IsNotNull,NotNull

findByAge(Is)NotNull

… where x.age not null

Like

findByFirstnameLike

… where x.firstname like ?1

NotLike

findByFirstnameNotLike

… where x.firstname not like ?1

StartingWith

findByFirstnameStartingWith

… where x.firstname like ?1(parameter bound with appended %)

EndingWith

findByFirstnameEndingWith

… where x.firstname like ?1(parameter bound with prepended %)

Containing

findByFirstnameContaining

… where x.firstname like ?1(parameter bound wrapped in%)

OrderBy

findByAgeOrderByLastnameDesc

… where x.age = ?1 order by x.lastname desc

Not

findByLastnameNot

… where x.lastname <> ?1

In

findByAgeIn(Collection<Age> ages)

… where x.age in ?1

NotIn

findByAgeNotIn(Collection<Age> age)

… where x.age not in ?1

True

findByActiveTrue()

… where x.active = true

False

findByActiveFalse()

… where x.active = false

IgnoreCase

findByFirstnameIgnoreCase

… where UPPER(x.firstame) = UPPER(?1)

posted @   cambra  阅读(200)  评论(0编辑  收藏  举报
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