实验3 类和对象_基础编程2

任务1

源码:

 1 #pragma once
 2 
 3 #include <iostream>
 4 #include <string>
 5 
 6 using std::string;
 7 using std::cout;
 8 
 9 // 按钮类
10 class Button {
11 public:
12     Button(const string &text);
13     string get_label() const;
14     void click();
15 
16 private:
17     string label;
18 };
19 
20 Button::Button(const string &text): label{text} {
21 }
22 
23 inline string Button::get_label() const {
24     return label;
25 }
26 
27 void Button::click() {
28     cout << "Button '" << label << "' clicked\n";
29 }
button.hpp
 1 #pragma once
 2 #include "button.hpp"
 3 #include <vector>
 4 #include <iostream>
 5 
 6 using std::vector;
 7 using std::cout;
 8 using std::endl;
 9 
10 // 窗口类
11 class Window{
12 public:
13     Window(const string &win_title);
14     void display() const;
15     void close();
16     void add_button(const string &label);
17 
18 private:
19     string title;
20     vector<Button> buttons;
21 };
22 
23 Window::Window(const string &win_title): title{win_title} {
24     buttons.push_back(Button("close"));
25 }
26 
27 inline void Window::display() const {
28     string s(40, '*');
29 
30     cout << s << endl;
31     cout << "window title: " << title << endl;
32     cout << "It has " << buttons.size() << " buttons: " << endl;
33     for(const auto &i: buttons)
34         cout << i.get_label() << " button" << endl;
35     cout << s << endl;
36 }
37 
38 void Window::close() {
39     cout << "close window '" << title << "'" << endl;
40     buttons.at(0).click();
41 }
42 
43 void Window::add_button(const string &label) {
44     buttons.push_back(Button(label));
45 }
window.hpp
 1 #include "window.hpp"
 2 #include <iostream>
 3 
 4 using std::cout;
 5 using std::cin;
 6 
 7 void test() {
 8     Window w1("new window");
 9     w1.add_button("maximize");
10     w1.display();
11     w1.close();
12 }
13 
14 int main() {
15     cout << "用组合类模拟简单GUI:\n";
16     test();
17 }
task1.cpp

 

运行结果截图:

 

问题1:

自定义了两个类,分别是Button(按钮类)和Window(窗口类);使用到了标准库的string类和vector类;Window类和Button类之间存在组合关系,vector类和Button类之间存在组合关系

问题2:

Button类中:click()函数较简单但可能会改变按钮的状态,适合设置inline,不适合添加const

Window类中:close()函数较简单但调用时会关闭窗口,改变对象的状态,不能添加const;add_button(const  string &label)函数较简单但会添加按钮改变对象的状态,适合设置inline,不能添加const

问题3:

string s(40, '*')用于创建一个长度为40,字符全部为*的字符串对象在后续输出Window类过程中用于分隔输出信息和其他信息,美化输出

 

 

任务2

源码:

 1 #include <iostream>
 2 #include <vector>
 3 
 4 using namespace std;
 5 
 6 void output1(const vector<int> &v) {
 7     for(auto &i: v)
 8         cout << i << ", ";
 9     cout << "\b\b \n";
10 }
11 
12 void output2(const vector<vector<int>> v) {
13     for(auto &i: v) {
14         for(auto &j: i)
15             cout << j << ", ";
16         cout << "\b\b \n";
17     }
18 }
19 
20 void test1() {
21     vector<int> v1(5, 42);
22     const vector<int> v2(v1);
23 
24     v1.at(0) = -999;
25     cout << "v1: ";  output1(v1);
26     cout << "v2: ";  output1(v2);
27     cout << "v1.at(0) = " << v1.at(0) << endl;
28     cout << "v2.at(0) = " << v2.at(0) << endl;
29 }
30 
31 void test2() {
32     vector<vector<int>> v1{{1, 2, 3}, {4, 5, 6, 7}};
33     const vector<vector<int>> v2(v1);
34 
35     v1.at(0).push_back(-999);
36     cout << "v1: \n";  output2(v1);
37     cout << "v2: \n";  output2(v2);
38 
39     vector<int> t1 = v1.at(0);
40     cout << t1.at(t1.size()-1) << endl;
41     
42     const vector<int> t2 = v2.at(0);
43     cout << t2.at(t2.size()-1) << endl;
44 }
45 
46 int main() {
47     cout << "测试1:\n";
48     test1();
49 
50     cout << "\n测试2:\n";
51     test2();
52 }
task2.cpp

 

运行结果截图:

 

问题1:

vector<int> v1(5, 42); // 创建一个包含5个42的vector类对象v1
const vector<int> v2(v1); // 创建一个常量vector类对象v2,初始值为v1的值

v1.at(0) = -999; // 把v1中索引为0的元素赋值为-999

问题2:

vector<vector<int>> v1{{1, 2, 3}, {4, 5, 6, 7}}; // 创建一个vector类对象,包含两个vector类的元素,分别为{1, 2, 3}和{4, 5, 6, 7}
const vector<vector<int>> v2(v1); // 创建一个常量vector类对象v2,初始值为v1的值

v1.at(0).push_back(-999); // 在v1中索引为0的子vector末尾添加一个元素-999

问题3:

vector<int> t1 = v1.at(0); // 创建一个vector类对象t1,赋值为v1的第一个子vector
cout << t1.at(t1.size()-1) << endl; // 输出t1的最后一个元素

const vector<int> t2 = v2.at(0); // 创建一个vector类对象t2,赋值为v2的第一个子vector
cout << t2.at(t2.size()-1) << endl; // 输出t2的最后一个元素

问题4:

(1)通过测试结果发现,v1和v2之间数据的修改是互不影响的,因此可以推测出vector内部封装的复制构造函数的实现机制是深复制

(2)由于v2是一个常量vector,使用 v2.at(0)访问其元素是可行的,说明vector 的 at()方法有一个const成员函数版本。因此至少需要提供一个const成员函数作为接口来保证访问安全,否则将无法对const vector进行访问

 

 

任务3

源码:

 1 #pragma once
 2 
 3 #include <iostream>
 4 #include <cassert>
 5 
 6 using std::cout;
 7 using std::endl;
 8 
 9 // 动态int数组对象类
10 class vectorInt{
11 public:
12     vectorInt(int n);
13     vectorInt(int n, int value);
14     vectorInt(const vectorInt &vi);
15     ~vectorInt();
16 
17     int& at(int index);
18     const int& at(int index) const;
19 
20     vectorInt& assign(const vectorInt &v);
21     int get_size() const;
22 
23 private:
24     int size;
25     int *ptr;       // ptr指向包含size个int的数组
26 };
27 
28 vectorInt::vectorInt(int n): size{n}, ptr{new int[size]} {
29 }
30 
31 vectorInt::vectorInt(int n, int value): size{n}, ptr{new int[size]} {
32     for(auto i = 0; i < size; ++i)
33         ptr[i] = value;
34 }
35 
36 vectorInt::vectorInt(const vectorInt &vi): size{vi.size}, ptr{new int[size]} {
37     for(auto i = 0; i < size; ++i)
38         ptr[i] = vi.ptr[i];
39 }
40 
41 vectorInt::~vectorInt() {
42     delete [] ptr;
43 }
44 
45 const int& vectorInt::at(int index) const {
46     assert(index >= 0 && index < size);
47 
48     return ptr[index];
49 }
50 
51 int& vectorInt::at(int index) {
52     assert(index >= 0 && index < size);
53 
54     return ptr[index];
55 }
56 
57 vectorInt& vectorInt::assign(const vectorInt &v) {  
58     delete[] ptr;       // 释放对象中ptr原来指向的资源
59 
60     size = v.size;
61     ptr = new int[size];
62 
63     for(int i = 0; i < size; ++i)
64         ptr[i] = v.ptr[i];
65 
66     return *this;
67 }
68 
69 int vectorInt::get_size() const {
70     return size;
71 }
vectorInt.hpp
 1 #include "vectorInt.hpp"
 2 #include <iostream>
 3 
 4 using std::cin;
 5 using std::cout;
 6 
 7 void output(const vectorInt &vi) {
 8     for(auto i = 0; i < vi.get_size(); ++i)
 9         cout << vi.at(i) << ", ";
10     cout << "\b\b \n";
11 }
12 
13 
14 void test1() {
15     int n;
16     cout << "Enter n: ";
17     cin >> n;
18 
19     vectorInt x1(n);
20     for(auto i = 0; i < n; ++i)
21         x1.at(i) = i*i;
22     cout << "x1: ";  output(x1);
23 
24     vectorInt x2(n, 42);
25     vectorInt x3(x2);
26     x2.at(0) = -999;
27     cout << "x2: ";  output(x2);
28     cout << "x3: ";  output(x3);
29 }
30 
31 void test2() {
32     const vectorInt  x(5, 42);
33     vectorInt y(10, 0);
34 
35     cout << "y: ";  output(y);
36     y.assign(x);
37     cout << "y: ";  output(y);
38     
39     cout << "x.at(0) = " << x.at(0) << endl;
40     cout << "y.at(0) = " << y.at(0) << endl;
41 }
42 
43 int main() {
44     cout << "测试1: \n";
45     test1();
46 
47     cout << "\n测试2: \n";
48     test2();
49 }
task3.cpp

 

运行结果截图:

 

问题1:

(1)通过测试结果发现,x2和x3之间数据的修改是互不影响的,因此可以推测出vectorInt类中,复制构造函数(line14)的实现,是深复制

(2)1)vectorInt类中,这两个at()接口,如果返回值类型改成int而非int&(相应地,实现部分也同步修改),测试代码不能正确运行  2)如果把line18返回值类型前面的const掉,存在潜在安全隐患,因为此时通过at()函数返回的值可以被修改,之后再将该函数的返回值绑定到一个引用变量时就可以改变at()函数的返回值,存在安全隐患

(3)vectorInt类中,assign()接口,返回值类型可以改成vectorInt,因为此处实现的是深复制,只需要将括号内成员的所有信息赋值给前面的成员即可

 

 

任务4

源码:

 1 #pragma once
 2 
 3 #include <iostream>
 4 #include <cassert>
 5 
 6 using std::cout;
 7 using std::endl;
 8 
 9 // 类Matrix的声明
10 class Matrix {
11 public:
12     Matrix(int n, int m);           // 构造函数,构造一个n*m的矩阵, 初始值为value
13     Matrix(int n);                  // 构造函数,构造一个n*n的矩阵, 初始值为value
14     Matrix(const Matrix &x);        // 复制构造函数, 使用已有的矩阵X构造
15     ~Matrix();
16 
17     void set(const double *pvalue);         // 用pvalue指向的连续内存块数据按行为矩阵赋值
18     void clear();                           // 把矩阵对象的值置0
19     
20     const double& at(int i, int j) const;   // 返回矩阵对象索引(i,j)的元素const引用
21     double& at(int i, int j);               // 返回矩阵对象索引(i,j)的元素引用
22     
23     int get_lines() const;                  // 返回矩阵对象行数
24     int get_cols() const;                   // 返回矩阵对象列数
25 
26     void display() const;                    // 按行显示矩阵对象元素值
27 
28 private:
29     int lines;      // 矩阵对象内元素行数
30     int cols;       // 矩阵对象内元素列数
31     double *ptr;
32 };
33 
34 // 类Matrix的实现:待补足
35 Matrix::Matrix(int n, int m) : lines(n), cols(m) {
36     ptr = new double[lines * cols];
37 }
38 
39 Matrix::Matrix(int n) : Matrix(n, n) {}
40 
41 Matrix::Matrix(const Matrix &x) : lines(x.lines), cols(x.cols) {
42     ptr = new double[lines * cols];
43     for (int i = 0; i < lines * cols; ++i) {
44         ptr[i] = x.ptr[i];
45     }
46 }
47 
48 Matrix::~Matrix() {
49     delete[] ptr;
50 }
51 
52 void Matrix::set(const double *pvalue) {
53     for (int i = 0; i < lines * cols; ++i) {
54         ptr[i] = pvalue[i];
55     }
56 }
57 
58 void Matrix::clear() {
59     for (int i = 0; i < lines * cols; ++i) {
60         ptr[i] = 0;
61     }
62 }
63 
64 const double& Matrix::at(int i, int j) const {
65     assert(i >= 0 && i < lines && j >= 0 && j < cols);
66     return ptr[i * cols + j];
67 }
68 
69 double& Matrix::at(int i, int j) {
70     assert(i >= 0 && i < lines && j >= 0 && j < cols);
71     return ptr[i * cols + j];
72 }
73 
74 int Matrix::get_lines() const {
75     return lines;
76 }
77 
78 int Matrix::get_cols() const {
79     return cols;
80 }
81 
82 void Matrix::display() const {
83     for (int i = 0; i < lines; ++i) {
84         for (int j = 0; j < cols; ++j) {
85             cout << ptr[i * cols + j] << ", ";
86         }
87         cout << "\b\b \n";
88     }
89 }
matrix.hpp
 1 #include "matrix.hpp"
 2 #include <iostream>
 3 #include <cassert>
 4 
 5 using std::cin;
 6 using std::cout;
 7 using std::endl;
 8 
 9 
10 const int N = 1000;
11 
12 // 输出矩阵对象索引为index所在行的所有元素
13 void output(const Matrix &m, int index) {
14     assert(index >= 0 && index < m.get_lines());
15 
16     for(auto j = 0; j < m.get_cols(); ++j)
17         cout << m.at(index, j) << ", ";
18     cout << "\b\b \n";
19 }
20 
21 
22 void test1() {
23     double x[1000] = {1, 2, 3, 4, 5, 6, 7, 8, 9};
24 
25     int n, m;
26     cout << "Enter n and m: ";
27     cin >> n >> m;
28 
29     Matrix m1(n, m);    // 创建矩阵对象m1, 大小n×m
30     m1.set(x);          // 用一维数组x的值按行为矩阵m1赋值
31 
32     Matrix m2(m, n);    // 创建矩阵对象m1, 大小m×n
33     m2.set(x);          // 用一维数组x的值按行为矩阵m1赋值
34 
35     Matrix m3(2);       // 创建一个2×2矩阵对象
36     m3.set(x);          // 用一维数组x的值按行为矩阵m4赋值
37 
38     cout << "矩阵对象m1: \n";   m1.display();  cout << endl;
39     cout << "矩阵对象m2: \n";   m2.display();  cout << endl;
40     cout << "矩阵对象m3: \n";   m3.display();  cout << endl;
41 }
42 
43 void test2() {
44     Matrix m1(2, 3);
45     m1.clear();
46     
47     const Matrix m2(m1);
48     m1.at(0, 0) = -999;
49 
50     cout << "m1.at(0, 0) = " << m1.at(0, 0) << endl;
51     cout << "m2.at(0, 0) = " << m2.at(0, 0) << endl;
52     cout << "矩阵对象m1第0行: "; output(m1, 0);
53     cout << "矩阵对象m2第0行: "; output(m2, 0);
54 }
55 
56 int main() {
57     cout << "测试1: \n";
58     test1();
59 
60     cout << "测试2: \n";
61     test2();
62 }
task4.cpp

 

运行结果截图:

 

总结:

1.利用assert检查输入的下标i,j是否合理

2.输出中使用退格\b进行格式控制

 

 

任务5

源码:

 1 #pragma once
 2 
 3 #include <iostream>
 4 #include <string>
 5 
 6 
 7 using std::string;
 8 using std::cin;
 9 using std::cout;
10 using std::endl;
11 
12 class User{
13 
14 public:
15     User(const string& name, const string& password = "123456", const string& email = "");
16 
17     void set_email();
18     void change_password();
19     void display() const;
20 
21 private:
22     string Name;
23     string Password;
24     string Email;
25 
26 };
27 
28 User::User(const string& name, const string& password, const string& email): Name(name), Password(password), Email(email) {}
29 
30 void User::set_email() {
31     cout << "Enter email address: ";
32     while(1) {
33         string email;
34         cin >> email;
35         size_t pos = email.find('@');
36         if (pos != string::npos) {
37             Email = email;
38             cout << "email is set successfully..." << endl;
39             break;
40         }
41         else {
42             cout << "illegal email.Please re-enter email: ";
43         }
44     }
45 }
46 
47 
48 void User::change_password() {
49     string old_password, new_password;
50     int count = 0;
51     while (count < 3) {
52         cout << "Enter old password: ";
53         cin >> old_password;
54         if (old_password == Password) {
55             cout << "Enter new password: ";
56             cin >> new_password;
57             Password = new_password;
58             cout << "new password is set successfully..." << endl;
59             return;
60         }
61         else {
62             cout << "password input error. Please re-enter angain: ";
63             count++;
64         }
65     }
66     cout << "password input error. Please try after a while." << endl;
67 }
68 
69 void User::display() const {
70     cout << "name:     " << Name << endl;
71     cout << "pass:     ";
72     for (auto i : Password) {
73         cout << "*";
74     }
75     cout << endl;
76     cout << "email:    " << Email << endl;
77 }
User.hpp
 1 #include <iostream>
 2 #include <vector>
 3 #include <string>
 4 
 5 using std::cin;
 6 using std::cout;
 7 using std::endl;
 8 using std::vector;
 9 using std::string;
10 
11 void test() {
12     vector<User> user_lst;
13 
14     User u1("Alice", "2024113", "Alice@hotmail.com");
15     user_lst.push_back(u1);
16     cout << endl;
17 
18     User u2("Bob");
19     u2.set_email();
20     u2.change_password();
21     user_lst.push_back(u2);
22     cout << endl;
23 
24     User u3("Hellen");
25     u3.set_email();
26     u3.change_password();
27     user_lst.push_back(u3);
28     cout << endl;
29 
30     cout << "There are " << user_lst.size() << " users. they are: " << endl;
31     for(auto &i: user_lst) {
32         i.display();
33         cout << endl;
34     }
35 }
36 
37 int main() {
38     test();
39 }
task5.cpp

 

运行结果截图:

 

总结:

1.利用标准库中的find()函数查找子串,用无符号整型类型size_t表示字符串索引

2.string s2(s1.size(), '*'); // 构造字符串对象s2, 包含和s1长度相同的*

 

任务6

源码:

 1 //date.h
 2 #ifndef __DATE_H__
 3 #define __DATE_H__
 4 class Date {    //日期类
 5 private:
 6     int year;        //
 7     int month;        //
 8     int day;        //
 9     int totalDays;    //该日期是从公元元年1月1日开始的第几天
10 public:
11     Date(int year, int month, int day);    //用年、月、日构造日期
12     int getYear() const { return year; }
13     int getMonth() const { return month; }
14     int getDay() const { return day; }
15     int getMaxDay() const;        //获得当月有多少天
16     bool isLeapYear() const {    //判断当年是否为闰年
17         return year % 4 == 0 && year % 100 != 0 || year % 400 == 0;
18     }
19     void show() const;            //输出当前日期
20     //计算两个日期之间差多少天
21     int distance(const Date& date) const {
22         return totalDays - date.totalDays;
23     }
24 };
25 #endif //__DATE_H__
date.h
 1 //date.cpp
 2 #include "date.h"
 3 #include <iostream>
 4 #include <cstdlib>
 5 using namespace std;
 6 namespace {    //namespace使下面的定义只在当前文件中有效
 7     //存储平年中的某个月1日之前有多少天,为便于getMaxDay函数的实现,该数组多出一项
 8     const int DAYS_BEFORE_MONTH[] = { 0, 31, 59, 90, 120, 151, 181, 212, 243, 273, 304, 334, 365 };
 9 }
10 Date::Date(int year, int month, int day) : year(year), month(month), day(day) {
11     if (day <= 0 || day > getMaxDay()) {
12         cout << "Invalid date: ";
13         show();
14         cout << endl;
15         exit(1);
16     }
17     int years = year - 1;
18     totalDays = years * 365 + years / 4 - years / 100 + years / 400
19                 + DAYS_BEFORE_MONTH[month - 1] + day;
20     if (isLeapYear() && month > 2) totalDays++;
21 }
22 int Date::getMaxDay() const {
23     if (isLeapYear() && month == 2)
24         return 29;
25     else
26         return DAYS_BEFORE_MONTH[month]- DAYS_BEFORE_MONTH[month - 1];
27 }
28 void Date::show() const {
29     cout << getYear() << "-" << getMonth() << "-" << getDay();
30 }
date.cpp
 1 //account.h
 2 #ifndef __ACCOUNT_H__
 3 #define __ACCOUNT_H__
 4 #include "date.h"
 5 #include <string>
 6 class SavingsAccount { //储蓄账户类
 7 private:
 8     std::string id;        //帐号
 9     double balance;        //余额
10     double rate;        //存款的年利率
11     Date lastDate;        //上次变更余额的时期
12     double accumulation;    //余额按日累加之和
13     static double total;    //所有账户的总金额
14     //记录一笔帐,date为日期,amount为金额,desc为说明
15     void record(const Date &date, double amount, const std::string &desc);
16     //报告错误信息
17     void error(const std::string &msg) const;
18     //获得到指定日期为止的存款金额按日累积值
19     double accumulate(const Date& date) const {
20         return accumulation + balance * date.distance(lastDate);
21     }
22 public:
23     //构造函数
24     SavingsAccount(const Date &date, const std::string &id, double rate);
25     const std::string &getId() const { return id; }
26     double getBalance() const { return balance; }
27     double getRate() const { return rate; }
28     static double getTotal() { return total; }
29     //存入现金
30     void deposit(const Date &date, double amount, const std::string &desc);
31     //取出现金
32     void withdraw(const Date &date, double amount, const std::string &desc);
33     //结算利息,每年1月1日调用一次该函数
34     void settle(const Date &date);
35     //显示账户信息
36     void show() const;
37 };
38 #endif //__ACCOUNT_H__
account.h
 1 //account.cpp
 2 #include "account.h"
 3 #include <cmath>
 4 #include <iostream>
 5 using namespace std;
 6 double SavingsAccount::total = 0;
 7 //SavingsAccount类相关成员函数的实现
 8 SavingsAccount::SavingsAccount(const Date &date, const string &id, double rate)
 9         : id(id), balance(0), rate(rate), lastDate(date), accumulation(0) {
10     date.show();
11     cout << "\t#" << id << " created" << endl;
12 }
13 void SavingsAccount::record(const Date &date, double amount, const string &desc) {
14     accumulation = accumulate(date);
15     lastDate = date;
16     amount = floor(amount * 100 + 0.5) / 100;    //保留小数点后两位
17     balance += amount;
18     total += amount;
19     date.show();
20     cout << "\t#" << id << "\t" << amount << "\t" << balance << "\t" << desc << endl;
21 }
22 void SavingsAccount::error(const string &msg) const {
23     cout << "Error(#" << id << "): " << msg << endl;
24 }
25 void SavingsAccount::deposit(const Date &date, double amount, const string &desc) {
26     record(date, amount, desc);
27 }
28 void SavingsAccount::withdraw(const Date &date, double amount, const string &desc) {
29     if (amount > getBalance())
30         error("not enough money");
31     else
32         record(date, -amount, desc);
33 }
34 void SavingsAccount::settle(const Date &date) {
35     double interest = accumulate(date) * rate    //计算年息
36                       / date.distance(Date(date.getYear() - 1, 1, 1));
37     if (interest != 0)
38         record(date, interest, "interest");
39     accumulation = 0;
40 }
41 void SavingsAccount::show() const {
42     cout << id << "\tBalance: " << balance;
43 }
account.cpp
 1 //6_25.cpp
 2 #include "account.h"
 3 #include <iostream>
 4 using namespace std;
 5 int main() {
 6     Date date(2008, 11, 1);    //起始日期
 7     //建立几个账户
 8     SavingsAccount accounts[] = {
 9             SavingsAccount(date, "03755217", 0.015),
10             SavingsAccount(date, "02342342", 0.015)
11     };
12     const int n = sizeof(accounts) / sizeof(SavingsAccount); //账户总数
13     //11月份的几笔账目
14     accounts[0].deposit(Date(2008, 11, 5), 5000, "salary");
15     accounts[1].deposit(Date(2008, 11, 25), 10000, "sell stock 0323");
16     //12月份的几笔账目
17     accounts[0].deposit(Date(2008, 12, 5), 5500, "salary");
18     accounts[1].withdraw(Date(2008, 12, 20), 4000, "buy a laptop");
19     //结算所有账户并输出各个账户信息
20     cout << endl;
21     for (int i = 0; i < n; i++) {
22         accounts[i].settle(Date(2009, 1, 1));
23         accounts[i].show();
24         cout << endl;
25     }
26     cout << "Total: " << SavingsAccount::getTotal() << endl;
27     return 0;
28 }
6_25.cpp

 

运行结果截图:

 

分析:

1.新定义了date类用来处理日期,使用户使用时能直接通过输入日期来进行相关操作,更符合实际情况

2.增设了部分描述信息并且增加了用于输出错误信息的函数,使类更加完善

3.该类仍然没有设计密码成员,与实际生活场景不符,可以仿照任务5设计一个password成员,提高安全性

 

posted @ 2024-11-04 15:43  吴婧希  阅读(18)  评论(0编辑  收藏  举报