读优&&输优
很nb的技巧……
但奇怪的是只能对文件使用……
然而交到OJ上或者比赛的时候都没有关系→_→
我大概也只能弄弄这些花里胡哨的东西了→_→
原理不清楚,背个板子好了
//minamoto #include<bits/stdc++.h> #define R register #define fp(i,a,b) for(R int i=(a),I=(b)+1;i<I;++i) #define fd(i,a,b) for(R int i=(a),I=(b)-1;i>I;--i) #define go(u) for(int i=head[u],v=e[i].v;i;i=e[i].nx,v=e[i].v) template<class T>inline bool cmin(T&a,const T&b){return a>b?a=b,1:0;} template<class T>inline bool cmax(T&a,const T&b){return a<b?a=b,1:0;} using namespace std; char buf[1<<21],*p1=buf,*p2=buf; inline char getc(){return p1==p2&&(p2=(p1=buf)+fread(buf,1,1<<21,stdin),p1==p2)?EOF:*p1++;} int read(){ R int res,f=1;R char ch; while((ch=getc())>'9'||ch<'0')(ch=='-')&&(f=-1); for(res=ch-'0';(ch=getc())>='0'&&ch<='9';res=res*10+ch-'0'); return res*f; } int read(char *s){ R int len=0;R char ch;while(((ch=getc())>'9'||ch<'0')); for(s[++len]=ch;(ch=getc())>='0'&&ch<='9';s[++len]=ch); return s[len+1]='\0',len; } double readdb() { R double x=0,y=0.1,f=1;R char ch; while((ch=getc())>'9'||ch<'0')(ch=='-')&&(f=-1); for(x=ch-'0';(ch=getc())>='0'&&ch<='9';x=x*10+ch-'0'); for(ch=='.'&&(ch=getc());ch>='0'&&ch<='9';x+=(ch-'0')*y,y*=0.1,ch=getc()); return x*f; } char sr[1<<21],z[20];int C=-1,Z=0; inline void Ot(){fwrite(sr,1,C+1,stdout),C=-1;} void print(R int x){ if(C>1<<20)Ot();if(x<0)sr[++C]='-',x=-x; while(z[++Z]=x%10+48,x/=10); while(sr[++C]=z[Z],--Z);sr[++C]='\n'; } const int P=998244353; inline void upd(R int &x,R int y){(x+=y)>=P?x-=P:0;} inline int add(R int x,R int y){return x+y>=P?x+y-P:x+y;} inline int dec(R int x,R int y){return x-y<0?x-y+P:x-y;} inline int mul(R int x,R int y){return 1ll*x*y-1ll*x*y/P*P;} int ksm(R int x,R int y){ R int res=1; for(;y;y>>=1,x=mul(x,x))(y&1)?res=mul(res,x):0; return res; }
深深地明白自己的弱小