LOJ#105. 文艺平衡树(FHQ Treap)

题面

传送门

题解

\(FHQ\ Treap\)比起\(Splay\)还是稍微好写一点……就是老是忘了要下穿标记……

//minamoto
#include<bits/stdc++.h>
#define R register
#define inline __inline__ __attribute__((always_inline))
#define fp(i,a,b) for(R int i=(a),I=(b)+1;i<I;++i)
#define fd(i,a,b) for(R int i=(a),I=(b)-1;i>I;--i)
#define go(u) for(int i=head[u],v=e[i].v;i;i=e[i].nx,v=e[i].v)
template<class T>inline bool cmax(T&a,const T&b){return a<b?a=b,1:0;}
template<class T>inline bool cmin(T&a,const T&b){return a>b?a=b,1:0;}
using namespace std;
char buf[1<<21],*p1=buf,*p2=buf;
inline char getc(){return p1==p2&&(p2=(p1=buf)+fread(buf,1,1<<21,stdin),p1==p2)?EOF:*p1++;}
int read(){
    R int res,f=1;R char ch;
    while((ch=getc())>'9'||ch<'0')(ch=='-')&&(f=-1);
    for(res=ch-'0';(ch=getc())>='0'&&ch<='9';res=res*10+ch-'0');
    return res*f;
}
char sr[1<<21],z[20];int K=-1,Z=0;
inline void Ot(){fwrite(sr,1,K+1,stdout),K=-1;}
void print(R int x){
    if(K>1<<20)Ot();if(x<0)sr[++K]='-',x=-x;
    while(z[++Z]=x%10+48,x/=10);
    while(sr[++K]=z[Z],--Z);sr[++K]=' ';
}
unsigned int aaa=19260817;
inline unsigned int rd(){aaa^=aaa>>15,aaa+=aaa<<12,aaa^=aaa>>3;return aaa;}
struct node;typedef node* ptr;
const int N=1e5+5;
inline void swap(R ptr &s,R ptr &t){R ptr p=s;s=t,t=p;}
struct node{
	ptr lc,rc;int t,sz,v;unsigned int pr;
	inline node();
	inline ptr init(R int val){return pr=rd(),v=val,sz=1,t=0,this;}
	inline ptr ppd(){return swap(lc,rc),t^=1,this;}
	inline ptr pd(){if(t)lc->ppd(),rc->ppd(),t=0;return this;}
	inline ptr upd(){return sz=lc->sz+rc->sz+1,this;}
}e[N],*rt=e,*pp=e;
inline node::node(){lc=rc=e;}
inline ptr newnode(R int v){return (++pp)->init(v);}
void split(ptr p,int k,ptr &s,ptr &t){
	if(p==e)return s=t=e,void();
	if(p->pd()->lc->sz<k)s=p,split(p->rc,k-p->lc->sz-1,p->rc,t);
		else t=p,split(p->lc,k,s,p->lc);
	p->upd();
}
ptr merge(ptr s,ptr t){
	if(s==e)return t;if(t==e)return s;
	if(s->pd()->pr<t->pd()->pr)return s->rc=merge(s->rc,t),s->upd();
	return t->lc=merge(s,t->lc),t->upd();
}
void rev(int l,int r){
	ptr s,t,p,q;
	split(rt,r,s,t),split(s,l-1,p,q);
	rt=merge(merge(p,q->ppd()),t);
}
void dfs(ptr p){
	if(p->pd()->lc!=e)dfs(p->lc);
	print(p->v);
	if(p->rc!=e)dfs(p->rc);
}
int main(){
//	freopen("testdata.in","r",stdin);
	int n=read(),m=read(),l,r;
	fp(i,1,n)rt=merge(rt,newnode(i));
	while(m--)l=read(),r=read(),rev(l,r);
	return dfs(rt),Ot(),0;
}
posted @ 2019-05-15 11:30  bztMinamoto  阅读(227)  评论(0编辑  收藏  举报
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