P4097 [HEOI2013]Segment

传送门

简单来说就是对于每条线段,先把它拆成\(O(logn)\)条,然后对于每一条再\(O(logn)\)判断在所有子区间的优劣程度

//minamoto
#include<bits/stdc++.h>
#define R register int
#define ls (p<<1)
#define rs (p<<1|1)
#define fp(i,a,b) for(R i=a,I=b+1;i<I;++i)
#define fd(i,a,b) for(R i=a,I=b-1;i>I;--i)
#define go(u) for(R i=head[u],v=e[i].v;i;i=e[i].nx,v=e[i].v)
inline int max(const R&x,const R&y){return x>y?x:y;}
inline int min(const R&x,const R&y){return x<y?x:y;}
using namespace std;
char buf[1<<21],*p1=buf,*p2=buf;
inline char getc(){return p1==p2&&(p2=(p1=buf)+fread(buf,1,1<<21,stdin),p1==p2)?EOF:*p1++;}
int read(){
    R res,f=1;char ch;
    while((ch=getc())>'9'||ch<'0')(ch=='-')&&(f=-1);
    for(res=ch-'0';(ch=getc())>='0'&&ch<='9';res=res*10+ch-'0');
    return res*f;
}
char sr[1<<21],z[20];int C=-1,Z=0;
inline void Ot(){fwrite(sr,1,C+1,stdout),C=-1;}
void print(R x){
    if(C>1<<20)Ot();if(x<0)sr[++C]='-',x=-x;
    while(z[++Z]=x%10+48,x/=10);
    while(sr[++C]=z[Z],--Z);sr[++C]='\n';
}
const int N=1e5+5;
struct node{
    int l,r,id;
    double yl,yr;
    node(int x1=0,int y1=0,int x2=0,int y2=0,int i=0){
        l=x1,r=x2;yl=y1,yr=y2;id=i;
        if (l==r) yl=yr=max(yl,yr);
    }
    double get(int x){return l==r?yl:yl+(k()*(x-l));}
    double k(){return (yr-yl)/(r-l);}
    void lm(int x){yl=get(x);l=x;}
    void rm(int x){yr=get(x);r=x;}
};
bool cmp(node a,node b,int x){
    return a.get(x)==b.get(x)?a.id<b.id:a.get(x)>b.get(x);
}
struct TR{
    node tr[N<<2];
    void build(int p,int l,int r){
        tr[p].l=l,tr[p].r=r;if(l==r)return;
        R mid=(l+r)>>1;
        build(ls,l,mid),build(rs,mid+1,r);
    }
    node query(int p,int l,int r,int x){
        if(l==r)return tr[p];node res;R mid=(l+r)>>1;
        res=(x<=mid)?query(ls,l,mid,x):query(rs,mid+1,r,x);
        return cmp(res,tr[p],x)?res:tr[p];
    }
    void update(int p,int l,int r,node x){
        if(tr[p].l>x.l)x.lm(tr[p].l);
        if(tr[p].r<x.r)x.rm(tr[p].r);
        R mid=(l+r)>>1;
        if(cmp(x,tr[p],mid))swap(tr[p],x);
        if(l==r||min(tr[p].yl,tr[p].yr)>=max(x.yl,x.yr))return;
        tr[p].k()<=x.k()?update(rs,mid+1,r,x):update(ls,l,mid,x);
    }
    void insert(int p,int l,int r,node x){
        if(x.l>r||x.r<l)return;
        if(tr[p].l>x.l)x.lm(tr[p].l);if(tr[p].r<x.r)x.rm(tr[p].r);
        if(l==x.l&&r==x.r)return (void)(update(p,l,r,x));
        if(l==r)return;R mid=(l+r)>>1;
        insert(ls,l,mid,x),insert(rs,mid+1,r,x);
    }
}T;
int lastans,cnt,n=39989,lim=1e9,m,op,k,x,y,xx,yy;node res;
int main(){
//	freopen("testdata.in","r",stdin);
    T.build(1,1,n);m=read();
    while(m--){
        op=read();
        if(!op){
            k=read(),k=(k+lastans-1)%n+1;
            lastans=T.query(1,1,n,k).id;
            print(lastans);
        }else{
            x=read(),y=read(),xx=read(),yy=read();
            x=(x+lastans-1)%n+1,xx=(xx+lastans-1)%n+1;
            y=(y+lastans-1)%lim+1,yy=(yy+lastans-1)%lim+1;
            if(x>xx)swap(x,xx),swap(y,yy);
            res=node(x,y,xx,yy,++cnt),T.insert(1,1,n,res);
        }
    }return Ot(),0;
}
posted @ 2018-12-04 14:35  bztMinamoto  阅读(207)  评论(0编辑  收藏  举报
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