HDCTF2023-Misc-wp

感谢Byxs20师傅的博客指导:https://byxs20.github.io/posts/21790.html

[HDCTF2023]ExtremeMisc

放进010editor里,发现有zip压缩包,foremost提取出来

image-20230422200701322

打开压缩包里面的文件需要密码

image-20230422200734186

直接爆破出来密码是haida

image-20230422200853698

得到一个Reserve.piz,放进010editor中,发现是个zip文件,但是每两位的hex值逆置了

image-20230422201201852

用脚本逆转过来,保存为zip文件

input_str = input()

output_str = ""
for i in range(0, len(input_str), 2):
    if i + 1 < len(input_str):
        output_str += input_str[i+1]
        output_str += input_str[i]
    else:
        output_str += input_str[i]
        
print(output_str)

打开压缩包,Plain.zip里的文件可以直接解压出来,secret.zip解压需要密码

image-20230422201314944

比较Plain.zip里的secret.txt,和secret中的secret.txt是一样的

image-20230422201527979

将secret.txt解压出来,用同种的压缩方式Store压缩

image-20230422201635133

然后明文攻击

image-20230423163004274

得到压缩包的密码,打开secret.zip,得到flag

NSSCTF{u_a_a_master_@_c0mpRe553d_PaCKe1s}

[HDCTF2023]MasterMisc

得到七个文件,放进010editor中发现是将一个zip分解成了7份,合并成一个zip,导出

image-20230422202043816

打开需要密码

image-20230422202151289

直接爆破出来密码是5483

image-20230422224240777

解压出来,放进010里

在这张png后面又有一张新png,导出来另存为flag.png

image-20230422202407086

image-20230422202505089

图片很小,可能是改变了宽高,用脚本爆破出图片的宽高

# -*- coding:utf-8 -*-

import struct
import zlib

def hexStr2bytes(s):
    b = b""
    for i in range(0,len(s),2):
        temp = s[i:i+2]
        b +=struct.pack("B",int(temp,16))
    return b

str1="49484452"  # 数据表示快,第一行的最后四位

str2="0802000000"   # CRC前五位

bytes1=hexStr2bytes(str1)
bytes2=hexStr2bytes(str2)
wid,hei = 350,43     #0x0141,0x014C

crc32 = "0x41DFCF32"

for w in range(wid,wid+2000):
    for h in range(hei,hei+2000):
        width = hex(w)[2:].rjust(8,'0')
        height = hex(h)[2:].rjust(8,'0')
        bytes_temp=hexStr2bytes(width+height)
        if eval(hex(zlib.crc32(bytes1+bytes_temp+bytes2))) == eval(crc32):
            print(hex(w),hex(h))

运行结果:0x15e 0x64

修改图片的宽高后得到了一段密文

image-20230422202735024

-7536-4433-bff

在010editor中的最后部分,也有一段密文

image-20230422224518417

f-96759901c405}

最后这段hex导出来,发现文件头是wav文件

image-20230422224732288

放进audacity,分析频谱图,得到第一部分的flag

image-20230422224806179

[HDCTF2023]SuperMisc

得到一张图片和一个.git文件

放进010里面,发现有很多的01,按照00和11导出来这些数据

写成一个二维码

扫描可以得到

11000#11111#10000#01111#11000#00011#11000#00011#00011#100#00011#01111#10000#00011#00011#00001#10000#00111#00011#00001#10000#00001#00011#11111#00011#11111#00111#100#00011#11000#00011#00001#10000#00001#10000#10000#00111#100#00011#00001#00011#00001#00011#11110#00011#00111#00111#100#10000#00111#00011#11111#00011#00001#00011#11110#00111#100#00011#00000#00011#11100#00011#00111#10000#00000#10000#00000#00011#11100#00011#00011#00011#11111#00011#11110#10000#00000#00011#10000#00011#00000

由0,1,#三个字符组成的有序字符串,morse密码

把01#分别替换为. - /

解码可以得到

image-20230424110114567

706173733D31633462346430302D373464662D343439322D623034392D353832656538333039653635

form hex 可以得到

image-20230424110148022

pass=1c4b4d00-74df-4492-b049-582ee8309e65

将得到的.git文件放进kali中

image-20230424133008004

分别用命令

git log
git reset --hard e9286.....

Snipaste_2023-04-23_23-38-34

得到一个zip包,打开需要密码

image-20230424110553433

密码就是刚刚得到的

查看文件发现是VMDK文件

image-20230424110805551

image-20230424111234247

发现了加密后的flag

看文件提示应该是维吉尼亚密码,明文是HDCTF

image-20230424112032506

得到密钥,在线解密

image-20230424112254056

[HDCTF2023]BabyMisc

打开得到一个文件和一个包

image-20230424113034690

包里放着很多文件,一直嵌套,到很久才能得到一个txt文件

image-20230424113423179

脚本提取出来

import os

def get_files(folder_path):
    files = []
    for filename in os.listdir(folder_path):
        full_path = os.path.join(folder_path, filename)
        if os.path.isdir(full_path):
            # 如果是文件夹,则递归获取其中的文件
            files.extend(get_files(full_path))
        else:
            # 如果是文件,则添加到文件列表中
            files.append(full_path)
    return files

folder_path = 'E:\Desktop\Script' # 替换为实际的文件夹路径

files = get_files(folder_path)

text = list(1000 * " ")
for file_path in files:
    count = int(file_path.split("\\")[-1][1:])
    with open(file_path, 'r') as f:
        text[count-1] = chr(int(f.read(), 16))
print(''.join(filter(lambda x: x != " ", text)))

得到

#!/bin/sh
inf1=$1;inf2=$2;ouf=$3;flag=$(wc-c${inf1}|cut-d''-f1);if[$(wc-c${inf2}|cut-d''-f1)-ge$flag];thenflag=$(wc-c${inf2}|cut-d''-f1);fi;sum_flag=0;flag1_flag=0;flag2_flag=0;FLAG=0;foriin$(seq0$(($flag+$flag)));doif[$FLAG-eq0];thenFLAG=1;ddif=$inf1of=$oufbs=1count=1seek=$sum_flagskip=$flag1_flagstatus=none;sum_flag=$(($sum_flag+1));flag1_flag=$(($flag1_flag+1));elseFLAG=0;ddif=$inf2of=$oufbs=1count=1seek=$sum_flagskip=$flag2_flagstatus=none;sum_flag=$(($sum_flag+1));flag2_flag=$(($flag2_flag+1));fidone

问ChatGPT说这是一个依次交换的脚本

image-20230424113834124

用脚本提取

with open("Encrypted.file", "rb") as f:
	data = f.read()

with open("1.7z", "wb") as f:
	f.write(data[1::2])

with open("base.txt", "wb") as f:
	f.write(data[::2])

得到一个7z和一个base

image-20230424114230501

将base32解码和rot47解码

image-20230424114338378

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nuw1%rpZdth4kPAjpYvo7ynkGNMP2aByvVHNIUFbFFbxHiqeK8nNNNG1U5esrOeJUar5s%D931GvUULYlsfTAuci00LeZzXy0wVs1lFE683TAnyxN5tHOTIIrxJDwpjH#RSQ2S%vUh0TU45e4QhE2Zq6cs9Yt5QST2nodEmJI4kxNcBv6757vsv6qGfP516CPtH250f%DeM3dSpfS51e09nWbrfO6DKlil0dy9aSOARMOZOZ1E1tnMyAswMekqDFp8KNi3QQ%oZyChf4UKfQAp701fkPj7Ps66xzrwIRMNKzTNeLAG5Qjupef2X2HCcHviQDQsdOk%Dx00RcyLVhQCMyrx1wcuqs#25sy7LxT2LAUNOaQ1JM1HFg7M9sp1aTVXtv1YfLnO%KFeCHt6cHZxtDqXWAJnf7tVnyJJJrXzE#PepXAQNOdu2vIYKr29SBUo3WV2aXyFB%W88BZxagH8klUR9O4fs6gHawEn0SNKsV1hNXoH2AZXxLTvUlFPmXYYZHM3lAJrnw%QGIqn9gn6XlLwipDacJEWCMjy8Q0Xl45vFin2jU5iv2gEFmL7MB#ApjqO5faAoVU%DQVAMPFcBi0bOfQh38AWBw2k1ANovnHLiiukjbHjd8xhOHl2ezijCqnyErK2xSy9%bxRIKlj8i4sFdqARGSYWkKwfdlK9x4HTeAjMeszDT6CEnx9auVQOFPsg2Pa6jAJ2%Ym0iR7WKnIx9oye8o057coGxqp6pFQs3UhoItucBbzig9BmauwQ8#FqeEo78ko9y%aJ1Ss0SOBg5rR5VNc4s9ZTH6mW0FnmlqRn07Y6ABAZHRkPWMdoYSSi6O3Rq#aasd%DesuotzsbmmWr5mnDrTpD334WlxH8IpGIR1Xe3#5rIYLtEuzvnt4SdnH2rhC9gys%Y2p85w2GhJFTURMi5yvu1O5ArtbDDS8ZHKMPY53deSDKM3Rm0siGwNzxZJnkHe33%gMWz2EymZloETqCEAtTUjPKy7qZSWaNK1HMWz8bLY6c4PfEavkIx96#4RW8KTlAp%N5yAt1ZMFXp9agj#3h3gLWNu9oeb7HfsfKQKn5mL5q07JkYJ4mJd42a7z5hBpnEu%MYCq2HegilbE5dRqgPfE#KdwgWvW9JgNjAgLqGvN5T5CtGYTlX#A6yxfc5C#DmRR%ZisuIlC855Xw9BWom5qoAQ6MoT#0aMxU5B86jiBFCV4Vq5tYIFshecfeYdlPAqy6%0VlphxulMc#MIcsCTWPfDF1QLpnEVl32HH3L5GQ5doGIoxkDovyD9XPVZ8u22MHv%#mYirPRBESVTTxKwlc1PEAP7ZXCla12nzbm10DbtY#kcElDHwrYyrBUyI7L1q5v3%rxUHtfWHPyyDWVC7tDJGSUUUGvXvN488WFtXLgnVi60nd02inQ2mVZYSCGDd3nAK%3mmlJ0QlSd643m0wJvNmm04mGf8CuBdDe2HuAN9EJPqD5V1kE5HV6MMm5T2s4M2U%UC0##8qk7Udku8wNPJM7VbI#vfNAtDVlMwRX7a7iKRFbxnWcmIC5#8UJQs8y4NPv%wPxSdqlTLrEIlIYpJb6A578phJ0R2JQcmL0GKgaOvd#l2UKkxqjFJT#KmNIaUkEe%uSqR80I7uqMSCPXwSCgroogtt2DYTDxYEGnLgXf2R5MdXTG##BZZvPrJMGzqStlS%TPT5zAl0OcWA2nv56Pq95dlhI15alwWbKzrhOMWoo5mEJyt5TREBaT9O39pet1w6%1f3spcWZztFgP587z1m9oirjwjoaRHGRX#j9HqELnylW3B5fwAwTWSgfyawivK45%dNspaDn4z1LhU7MYwqmZXMraNfdPM0h0M85Iwj856ivmqZeQtocYmuT7cZor225K%Ze04KfOHOM3LERAtjCw5QADP5H57E7tEIKRBmqKSxFAUdBMhtuikhzCNqpbljWxh%LaLI1nI8q32hRn0ZdwzLJ5kV9zQZ0Cu8aBaS#MK19kM3iVMYV0YrfBrtLvKEd7il%kmUQegpRZYZpjxxpeFa54EfzDp9IxPTwvhGT6RFMzzRifY0DSsQS2VL#3zbCrLmU%aJewvZQsnPnuukP5GqfenowRr6cYKxoXzr6bMeR5zj3Fn5r9mVnzvloGwWiPQGPd%URQG7PACwdf#y50frgLOY9n4bug9M8FzgkTiO84qCzQGErWgt99J5EQc9MirtJkb%mheRAFFKNkTDWz5RFdbCMip5KByX8zdisMskBFMREqx856Z0#K#DtSYPuaRVomga%OjuYL4mRBmmi5Esf3t6IIH7tCyDiFeXs7OrVduze13KfoDy4SVQgNay5ZkvlfHHb%V6nGabo3dbCRt5DwRRChugkLaRmS5qWLzD5h3fNA9xPFW70Tr6ayjTAqRv06IG0k%DnNf0RrGpMkgB1uluhifhwSvLpIyj9HC5UEXM#C1wG3CoVaayRL1L5sdWAkFx6HA%IAfDd1D9lB155DllM2PKmusv2nZvOrn2sx5gcWHQFYklP9UDcR5#b5B5ft7tEeZT%WpUdHktGcby4NesACI9aWhEKtnnrVaaKK4jGVtbPimnIBjPwm1dEVZnCRG0v74O3%QJ2frLFUz2Ii6pkDJFGm2n0EIylNLcjiY#NGH2PF1p5GFoGpXj2tjuUz8wjA9tpx%BEla8NHGg2GcU0Nsart7f6bQx1#QzA#ln9JXLlEIBsUAb5hzxUFLOzeFqjTD55I#%kr1D9#S#x5X6N3qTXrUzA05Bb4Dib8I7xJ5vI3qjWD5vZhNIshitQtL3zsVpZs2Q%MbMu0OIPZ5#DJsrJzw5oM2325RPsl6vneEVdP##macF2vh6ROdLE4j7jd189d159%lvh6cOKuTpslIwx5wL0A4XntzC492DQeCwAtv2pG1FeygWghovJQJv0XGz0Dlkma%BDwzRZmMv99Jt8IqC5#V1jR9QayCdshJccP4pK4Bctb53sqfHqtZ47xX5SideoHE%d2I7Aqr0oF5c#Zf5ou8d6OU8slxCfFIA7Pf8R8EwoJjaLVWohQ6fjXZt0BdAoYRi%YHcpdXLCIZ9yjuqvdtKZhYltcbq9SHJybxkdirOZG#QNpnOzMcPyWKoQDpLTVkkr%m3jWQP#j59vbk3qO5O5r2UIATzukIZDGST3L2vLejq6FBEBLNvEqn04qIVsEXmJg%YlIjDZDPr9375eTji5U3SVp2XpyVkOQK36EYsuNhuamwUrKZcuOatMLydrfMP0jh%a57Xa5IrxwdFJNQ9sNkjd2mv2yGeeBUf6Fqm5fqTjI5iQ3t5LefVKB3gDtwHX1y#%uUyNn5cRNF7Z5EcPtgUcrIqzWD0xHaI4onRJRt75Y2nvZO7SoQycjlveBpXZQDSU%n2mlENJhBN4WC5xPuYs6AR1IqjL5l6aIhQDQodgk2uCYTPuRjiPttc0mr4xH3tVs%QXhk3rV2oQ0B5ImSyYsjji1NZNuSArvp551xLev5590Sy5fEtuy82jXholZpL1iP%jwmdGd91bGdeW3vb6DmN7r3SbC0eL7eN5AYsqg1NbyGogpbrtKR7Uu5r4eNthFQo%8a0J65OAynDyOw0uJnWTYlB9NXdYyRKBTNlqZLT6fyYZ3ULD54r8CRbk4VFNrMK3%67UDTm6dLM0z1bAbOdJ242YE1RfvH0V6y3X8#ITXt5HRvKJ9sskmOsLOerCE6CZM%7Fj7K0UiAdT5qy7ebe8XAINgAySY9TVQWDaZvHSb0ZQVQcsR157LzDNV#tK0tT5v%8b1pOdGmGDDKqJhdsjDwH2HbUQAkGgEEmQnh##GlNCXMveNp0W6qB3990ZrnOeuK%CPswYU5cdNSXsPfS07k6t25GfXTnUW78zygMxCxZi4MzwNdrrRLxEso87wO3C5l5%0zWGCRwseHaiYTjOfH3m5AsH1sWXy#KfLAJpfdyrBoIkwsRXtgWwd#MMpfu51984%QxdEPLRZtvn4RM5TMHqvL9fTmFeycugkuz9MufX37iJ8S8xvL3#5YhEL#p4WqqNv%P8xS#QYNvEzT3Avq3PFi4p5YCG1ux635uP9bLXQDCaJyNFaWan3vr8WuWHI3kmqO%I3TEDZIZO6AkAVfZrS5o#BIdR8RrmB1xAmUsAw5OGZZFRUJFkMdRyb0#VXHXlwnG%5HIKqkoTwqnwWvbvz6yz0Mk5EUIKbNQQqhIvzyfwy#uRfQf5fqlJs5lgoLmyiY1Y%Mm6RDRURgH7O#5m2jTDLrqcz7#iFcR4k5SMyFaJilcJ9nlUjGZrAt23RNHyG76rk%XgqruNK5EiPjcE6tzuC3#UI75SgXY7mOZgR7D4uV4sTI7CqG0USRDyO9j28VFuB9%l8yYCSboLpD8AqtW5fpCzPoHVmu4jaX5XiLMPPB4m7H4wNbsQZaoKq9#9LFWxA55%ZdMLLBqCjiQDA8hqjL1P8QzMDqQfjGLzcC#KsFBMGhssh6lgHiNwI5x3udyDp6fe%Pr41N5YLIPPXQKxGHTD2yQAKju4E9fUTJ#eC62ABH8YZnelvjZ1gk9hkCY3BsFqR%KRqqgCrk4MJxcapkS6C8lfp0scp3w8JM1PguwOb4zPK1u2IitI6KStLneTOvpj3c%TDZD2UbrgXdZz5rWqXDgzADalALMO56V5agoMyHlLZ3Yh0unhOrI7MMo20#L8iwn%HGvVifk1mcC9Qi5EVU#2b5r26SHSulfSHkNjq#dyE97ttagpCEDsQLG2K9FEQyO4%5n05z7ivuoDCLBeQQ54g7SMPWAxjJzPTQnZ43U3bBKCRIDnYQXMox1Lm20uqBBHd%EpOcWH21ue5lyU#xcm5sXvSKwF25soep0OMwFDyIzMFkyQnI#EoOVdzamOCyzRgC%UAq5vAYICpRl3tztcBp5MXTtswUbkMwI84BBO2eN5Om7m7Sb1ABIIr2EVKpE#6sk%Z2brhVLAgocw5RxNXMqcUSDjDUNlI5kcs1A7k9WsN9gYP5#tWz3vu#Dgp#hDyUMu%RNG7onzs0XJwg2vZpnVm0rJljeYpQzJkgGC5Fp2HzUKr0kl67tMN#fPos5IvPDjH%B5vLy4WZXKIqIH7QU8YfLDLzew8G1DSt36Nvr2Kc#TqJVd29m60yMNTOJm0lH5jI%icrWQ4Yydn8gwb5J4UlNxL1Kp5C6inm2N1TYYTBEnQkwjHZd527rzuyYqXZgH#8v%OTht50v42r3WWHNd2dDxW9Mova4FYc9Ogix9emkShvHoCsWTPx9hTpXgltzsXeMe%tcehgu9iixLePsHgg#UorxGN7zYkSvYrg1or5dO3xEQzoLzFAsSKNN2Yfl5xsjtE%Dui7oUz#x5ik4Q2P1jc5Xm6f7x2pW9l7##qxKU#83#To4ibapnz6g6ILqBNGVlKa%2G6nlzqAbuF7y9ije5e56VaLUOZeLo1KjmpXfDrKeG9iv5BC5HygfaI2qc7G9dtj%RveWLKhVQyIJ35ifUwGD#JEm5W#WGgpn85xB6Wir13Kyte#Th9RHbH#G2XwbB1mC%7tswHpya3M8535KhRjzLNPpcaUMB6SaZSl8UoinCpJvriiukUCAlHtc5nlupa67b%Z#AnjAo1CHuNaVz3J#lWxBV3L462CDic39T8u500IALwSa9rJE5CvY8eQhYpqsCX%vbOz7#ebB0R1KajkEqPwWaBpkyZ78fo8m0n#HejcWUGOHVQ5#mrZ2HsjkOVu8pUJ%VCuOhJZtTyWIumzji#IbCeJJtL2rxW0K6h5FEtlqqI6jhB2VkAJu##5VbFQtShR2%fUVBeQSsO9vDb4nuVs#Oahdp6GYS5d4Iu98sIBB1uEE

解压得到了一个pmf的命名的文件,这个pmf文件是 DiskGenius 备份后的一种文件格式,改一下名字为 1.pmf,拖到 DG 里面就好了

image-20230424114918093

image-20230424115059700

得到三个zip和一个图片,看名字也是lsb

image-20230424123329066

将得到的txt中多余的部分删除

但是这里保存的txt是unix,要在window下重新保存

image-20230424125917921

名字为key.txt

image-20230424125953259

打开第三个压缩包,一看就是明文攻击

而且这里必须用7z压缩

不多说,明文攻击,根据新教程,也可以判断这个是7z压缩的,链接:https://byxs20.github.io/posts/30731.html

image-20230424125502052

posted @ 2023-04-24 13:32  bzbzzbc  阅读(282)  评论(0编辑  收藏  举报