leetcode面试准备:Valid Anagram

leetcode面试准备:Valid Anagram

1 题目

Given two strings s and t, write a function to determine if t is an anagram of s.

For example,
s = "anagram", t = "nagaram", return true.
s = "rat", t = "car", return false.

Note:
You may assume the string contains only lowercase alphabets.
接口: public boolean isAnagram(String s, String t)

2 思路

题意

对比两个字符串是否是一样的。

解

HashMap思想存储字符，字符串s往map里面存储，字符串t往map里面取。最后看map是否为空：if 空，true.
复杂度: Time: O(n) , Space:O(26)

3 代码

    public boolean isAnagram(String s, String t) {
        Map<Character, Integer> smap = new HashMap<Character, Integer>();
        int slen = s.length();
        int tlen = t.length();
        if (slen != tlen) 
        	return false;
        for (int i = 0; i < slen; i++) {
        	Character c = s.charAt(i);
        	if (smap.containsKey(c)) {
        		int count = smap.get(c);
        		count++;
        		smap.put(c, count);
        	} else {
        		smap.put(c,1);
        	}
        }
        
        for (int i = 0; i < tlen; i++) {
        	Character c = t.charAt(i);
        	if (smap.containsKey(c)) {
        		int count = smap.get(c);
        		count--;
        		if(count == 0) {
        			smap.remove(c);
        		} else {
        			smap.put(c, count);
        		}
        	} else {
        		return false;
        	}
        }
        return smap.isEmpty();
    }

4 总结

HashMap思想。