「SCOI2015」小凸想跑步 解题报告
「SCOI2015」小凸想跑步
最开始以为和多边形的重心有关,后来发现多边形的重心没啥好玩的性质
实际上你把面积小于的不等式列出来,发现是一次的,那么就可以半平面交了
Code:
#include <cstdio>
#include <cmath>
#include <algorithm>
#define Vector Point
const int N=2e5+10;
const double eps=1e-7;
int n,m,l,r;
struct Point
{
double x,y;
Point(){}
Point(double X,double Y){x=X,y=Y;}
double angle(){return atan2(y,x);}
Vector friend operator +(Vector a,Vector b){return Vector(a.x+b.x,a.y+b.y);}
Vector friend operator -(Vector a,Vector b){return Vector(a.x-b.x,a.y-b.y);}
Vector friend operator *(Vector a,double b){return Vector(a.x*b,a.y*b);}
}bee[N],q1[N];
struct Line
{
Point s,t;double ang;
Line(){}
Line(Point S,Point T){s=S,t=T,ang=(t-s).angle();}
}yuu[N],q2[N];
double Cross(Vector a,Vector b){return a.x*b.y-a.y*b.x;}
bool isrig(Line a,Point b){return Cross(b-a.s,a.t-a.s)>0;}
bool cmp(Line a,Line b){return fabs(a.ang-b.ang)<eps?isrig(a,b.t):a.ang<b.ang;}
Point jd(Line a,Line b){return a.s+(a.t-a.s)*(Cross(a.s-b.s,b.t-b.s)/Cross(b.t-b.s,a.t-a.s));}
void SI()
{
std::sort(yuu+1,yuu+1+m,cmp);
q2[l=r=1]=yuu[1];
for(int i=2;i<=m;i++)
if(fabs(yuu[i].ang-yuu[i-1].ang)>eps)
{
while(l<r&&isrig(yuu[i],q1[r-1])) --r;
while(l<=r&&isrig(yuu[i],q1[l])) ++l;
q1[r]=jd(q2[r],yuu[i]);
q2[++r]=yuu[i];
}
while(l<r&&isrig(q2[l],q1[r-1])) --r;
q1[r]=jd(q2[l],q2[r]);
}
double area()
{
if(r-l<2) return 0;
double ret=0;
for(int i=l;i<r;i++) ret+=Cross(q1[i],q1[i+1]);
ret+=Cross(q1[r],q1[l]);
return ret/2;
}
int main()
{
scanf("%d",&n);m=n;double sum=0;
for(int i=1;i<=n;i++)
{
scanf("%lf%lf",&bee[i].x,&bee[i].y);
yuu[i]=Line(bee[i-1],bee[i]);
if(i!=1) sum+=Cross(bee[i-1],bee[i]);
}
yuu[1]=Line(bee[n],bee[1]);
sum+=Cross(bee[n],bee[1]);
sum/=2;
bee[++n]=bee[1];
for(int i=3;i<=n;i++)
{
double A=bee[1].y-bee[2].y-(bee[i-1].y-bee[i].y);
double B=bee[2].x-bee[1].x-(bee[i].x-bee[i-1].x);
double C=Cross(bee[1],bee[2])-Cross(bee[i-1],bee[i]);
if(fabs(A)<eps) yuu[++m]=Line(Point(0,-C/B),Point(0,-C/B)+Vector(-B,A));
else yuu[++m]=Line(Point(-C/A,0),Point(-C/A,0)+Vector(-B,A));
}
SI();
printf("%.4f\n",area()/sum);
return 0;
}
2019.3.4