springmvc REST风格的URL
1:需要配置一个filter
<!-- 配置 org.springframework.web.filter.HiddenHttpMethodFilter: 可以把 POST 请求转为 DELETE 或 PUT 请求 --> <filter> <filter-name>HiddenHttpMethodFilter</filter-name> <filter-class>org.springframework.web.filter.HiddenHttpMethodFilter</filter-class> </filter> <filter-mapping> <filter-name>HiddenHttpMethodFilter</filter-name> <url-pattern>/*</url-pattern> </filter-mapping>
2:在页面上请求 PUT和DELETE都是有post转换的。放在隐藏域中
<a href="first/testRest/1">testRest GET</a> <br><br><br> <form action="first/testRest/1" method="post"> <input type="hidden" name="_method" value="PUT"/> <input type="submit" value="TestRest PUT"/> </form> <br><br> <form action="first/testRest/1" method="post"> <input type="hidden" name="_method" value="DELETE"/> <input type="submit" value="TestRest DELETE"/> </form> <br><br> <form action="first/testRest" method="post"> <input type="submit" value="TestRest POST"/> </form> <br><br>
3:在java类中写对应的方法
/** * Rest 风格的 URL. 以 CRUD 为例: 新增: /order POST 修改: /order/1 PUT update?id=1 获取: * /order/1 GET get?id=1 删除: /order/1 DELETE delete?id=1 * * 如何发送 PUT 请求和 DELETE 请求呢 ? 1. 需要配置 HiddenHttpMethodFilter 2. 需要发送 POST 请求 * 3. 需要在发送 POST 请求时携带一个 name="_method" 的隐藏域, 值为 DELETE 或 PUT * * 在 SpringMVC 的目标方法中如何得到 id 呢? 使用 @PathVariable 注解 * */ @RequestMapping(value = "/testRest/{id}", method = RequestMethod.PUT) public String testRestPut(@PathVariable Integer id) { System.out.println("testRest Put: " + id); return SUCCESS; } @RequestMapping(value = "/testRest/{id}", method = RequestMethod.DELETE) public String testRestDelete(@PathVariable Integer id) { System.out.println("testRest Delete: " + id); return SUCCESS; } @RequestMapping(value = "/testRest", method = RequestMethod.POST) public String testRest() { System.out.println("testRest POST"); return SUCCESS; } @RequestMapping(value = "/testRest/{id}", method = RequestMethod.GET) public String testRest(@PathVariable Integer id) { System.out.println("testRest GET: " + id); return SUCCESS; }