1011 A+B和C (15)

//PAT1011
//这题就是死磕自己....
//考虑a,b同号溢出问题，若同号转a > c - b, 异号直接相加判断

#include <iostream>

using namespace std;

inline bool isSame(int a, int b)
{
	return ( a > 0 && b > 0 ) || ( a < 0 && b < 0 );
}

int main()
{
	int a, b, c;
	int t;
	int cnt = 1;
	cin>>t;
	while ( cnt <= t )
	{
		cin>>a>>b>>c;
		bool flag = false;
		if ( isSame(a, b) )			//若a,b同号
		{
			if ( a > 0 )
			{
				if ( c > 0 )		//a, b, c > 0
					flag = ( a > (c - b) );		//a + b > c 转为 a>(c -b )
				else				//a, b > 0, c <= 0, 结果必为真
					flag = true;
			}
			else
			{
				if ( c < 0 )		//同上，a,b,c < 0
					flag = ( a > (c - b) );
				else				//同上a, b < 0, c >= 0, 结果必为真
					flag = false;
			}
		}
		else						//a,b异号
			flag =  ( a + b > c );
		if ( flag )
		{
			cout<<"Case #"<<cnt++<<": true"<<endl;
		}
		else
		{
			cout<<"Case #"<<cnt++<<": false"<<endl;
		}
	}
	return 0;
}