摘要：
function submitForm(){ var submitUrl = url; $.ajax({ type: "POST", url: submitUrl, data: { "loginUser.user_name": $("#UserName").val() , "user.password": $("#password").val() , "randCode": $("#randCode").val() }, beforeSend: funct 阅读全文
posted @ 2012-05-07 22:16 bug yang 阅读(250) 评论(0) 推荐(0) 编辑