获取连续递增1数据段的简单程序（可用于从含缺失值的时间序列数据中获取时间连续且持续时间大于某一值的数据段）

 

以下是一个通过matlab获取连续递增1数据段的简单编程方法，可用于从含缺失值的时间序列数据中获取时间连续且持续时间大于某一值的数据段

# 程序

% Example original data
data0 = randn(1,18)
time0 = 1:18;
% Example time corresponding to the valid data
time1 = [1, 2, 3, 5, 7, 8, 10, 11, 12, 13, 15, 17]
% Calculate the difference between adjacent elements
d = diff(time1)
% Find the indexes where the difference is not equal to 1
idx = find(d ~= 1)
% Add 1 to the indexes to get the starting positions of segments
starts = [1, idx+1]
% Calculate the segment lengths
lens = diff([starts, numel(time1)+1])
% Get the time segments with a continuous increment of 1
segmentsA = arrayfun(@(s,l) time1(s:s+l-1), starts, lens, 'UniformOutput', false)
% Get the time segments with len>=3
segmentsB = arrayfun(@(s,l) time1(s:s+l-1), starts( find(lens>=3) ), lens( find(lens>=3) ), 'UniformOutput', false)
% Display the time segments
disp(segmentsB);
%Get the required data
dataB = cell(length(segmentsB),1)
for i = 1:length(segmentsB)
    dataB{i,1} = data0(segmentsB{i});
end
dataB

　　

# 运行结果