19-短信登录接口

短信登录接口

urls.py

from django.urls import path, include
from rest_framework.routers import SimpleRouter
from . import views

router = SimpleRouter()
router.register('', views.SendSmsView, 'send')  # 此处第一个参数不要加上,因为视图类中使用了actions,会把该视图名添加进来

urlpatterns = [
	path('', include(router.urls)),
]

serializer.py

# 验证码登录
class Codeserializers(serializers.ModelSerializer):
	code = serializers.CharField()  # code字段在数据库中不存在,所以需要自己定义

	class Meta:
		model = models.User
		fields = ['telephone', 'code']

	# 验证码登录+token签发
	def validate(self, attrs):
		user = self._get_user(attrs)
		token = self._get_token(user)
		self.context['token'] = token
		self.context['user'] = user
		return attrs

	# 验证码登录逻辑
	def _get_user(self, attrs):
		telephone = attrs.get('telephone')
		code = attrs.get('code')  # 此处也还有个问题
		# 先校验验证码是否匹配
		cache_code = cache.get(settings.PYTHON_CACHE_KEY.format(telephone))

		print("前端获取:", code, type(code))
		print("缓存获取:", cache_code, type(cache_code))
		# if cache_code == code: 此处是因为没有腾讯短信,所以就简单一点,手动发送验证码
		if cache_code == code:
			# 验证码校验通过
			if re.match('^1[3-9][0-9]{9}$', telephone):
				user = models.User.objects.filter(telephone=telephone).first()
				if user:  # 验证码和手机号码都正确,返回当前用户对象
					# 代码能执行到此处,就说明一切信息都正确,就将cache_code资源置空
					cache.set(settings.PYTHON_CACHE_KEY.format(telephone, ), "")
					# 返回当前对象
					return user
				else:
					raise ValidationError('验证码正确,手机号码错误!')
			else:
				raise ValidationError('手机号码格式错误!')
		else:
			raise ValidationError('验证码错误!')

	# 签发token
	def _get_token(self, user):
		from rest_framework_jwt.serializers import jwt_payload_handler, jwt_encode_handler
		payload = jwt_payload_handler(user)
		token = jwt_encode_handler(payload)
		return token

views.py

class SendSmsView(ViewSet):
	throttle_classes = (SmsThrottling,)
	# 验证登录视图接口
	@action(methods=('POST',), detail=False)
	def code_login(self, request, *args, **kwargs):
		ser = serializer.Codeserializers(data=request.data)
		if ser.is_valid():
			token = ser.context['token']
			username = ser.context['user'].username
			return APIResponse(token=token, username=username)
		else:
			return APIResponse(code=0, msg='Error', result=ser.errors)

posted @ 2021-02-22 16:32  今天捡到一百块钱  阅读(168)  评论(0编辑  收藏  举报