循环-10. 求序列前N项和*
1 /* 2 * Main.c 3 * C10-循环-10. 求序列前N项和 4 * Created on: 2014年7月30日 5 * Author: Boomkeeper 6 *******部分通过******* 7 */ 8 9 #include <stdio.h> 10 11 int main(void) { 12 13 double sum = 0.0; //记录前N项和 14 int numerator = 2,denominator = 1; //分子分母 15 int N; //题目中的N 16 int i;//循环使用 17 int tem = 0; 18 19 scanf("%d", &N); 20 21 if (N == 1) 22 printf("%.2f\n", (double) numerator / denominator); 23 else { 24 sum = (double) numerator / denominator; 25 for (i = N; i > 1; i--) { 26 tem = denominator; 27 denominator = numerator; 28 numerator = numerator + tem; 29 sum += (double) numerator / denominator; 30 } 31 printf("%.2f\n", sum); 32 } 33 34 return 0; 35 }
不完美...
题目链接：
http://pat.zju.edu.cn/contests/basic-programming/%E5%BE%AA%E7%8E%AF-10
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