leetcode 53. Maximum Subarray
Given an integer array nums
, find the contiguous subarray (containing at least one number) which has the largest sum and return its sum.
Example:
Input: [-2,1,-3,4,-1,2,1,-5,4]
,
Output: 6
Explanation: [4,-1,2,1]
has the largest sum = 6
.
Follow up:
If you have figured out the O(n) solution, try coding another solution using the divide and conquer approach, which is more subtle.
贪心:
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 | class Solution( object ): def maxSubArray( self , nums): """ :type nums: List[int] :rtype: int """ ans = s = nums[ 0 ] for i in xrange ( 1 , len (nums)): if s > 0 : s = nums[i] + s else : s = nums[i] ans = max (s, ans) return ans |
DP解法://dp[i] means the maximum subarray ending with A[i];
1 2 3 4 5 6 7 8 9 10 11 12 | class Solution( object ): def maxSubArray( self , nums): """ :type nums: List[int] :rtype: int """ dp = [ 0 ] * len (nums) ans = dp[ 0 ] = nums[ 0 ] for i in xrange ( 1 , len (nums)): dp[i] = max (dp[i - 1 ] + nums[i], nums[i]) ans = max (ans, dp[i]) return ans |
递归解法:
TODO
标签:
leetcode
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