【HDOJ】2386 Dart Challenge

纯粹母函数+滚动数组,水之。

 1 /* 2386 */
 2 #include <iostream>
 3 #include <string>
 4 #include <map>
 5 #include <queue>
 6 #include <set>
 7 #include <stack>
 8 #include <vector>
 9 #include <algorithm>
10 #include <cstdio>
11 #include <cmath>
12 #include <ctime>
13 #include <cstring>
14 #include <climits>
15 #include <cctype>
16 using namespace std;
17 
18 const int maxn = 20005;
19 
20 int cnt[305];
21 int score[305];
22 bool f[2][maxn];
23 
24 int main() {
25     int i, j, k;
26     int t, tt;
27     int n, m;
28     int ans, mx;
29     int cur, pre;
30     
31     #ifndef ONLINE_JUDGE
32         freopen("data.in", "r", stdin);
33         freopen("data.out", "w", stdout);
34     #endif
35     
36     scanf("%d", &tt);
37     for (t=1; t<=tt; ++t) {
38         scanf("%d %d", &n, &m);
39         memset(cnt, 0, sizeof(cnt));
40         mx = 0;
41         for (i=0; i<n; ++i) {
42             scanf("%d", &k);
43             mx = max(k, mx);
44             ++cnt[k];
45             ++cnt[k<<1];
46             ++cnt[(k<<1)+k];
47         }
48         --cnt[(mx<<1)+mx];
49         for (n=i=0; i<305; ++i)
50             if (cnt[i])
51                 score[n++] = i;
52         memset(f, false, sizeof(f));
53         f[0][0] = f[1][0] = true;
54         
55         for (j=1, cur=1, pre=0; j<=m; ++j, pre=cur, cur=!cur) {
56             for (i=0; i<=score[n-1]*j; ++i) {
57                 for (k=0; k<n; ++k) {
58                     if (f[pre][i] && i+score[k]<maxn)
59                         f[cur][i+score[k]] = true;
60                 }
61             }
62         }
63         ans = 0;
64         for (i=0; i<=score[n-1]*m; ++i)
65             if (f[pre][i])
66                 ++ans;
67         printf("Scenario #%d:\n%d\n\n", t, ans);
68     }
69     
70     #ifndef ONLINE_JUDGE
71         printf("%d\n", (int)clock());
72     #endif
73     
74     return 0;
75 }

 

posted on 2015-04-16 11:13  Bombe  阅读(166)  评论(0编辑  收藏  举报

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