【HDOJ】1474 Always On the Run

普通DP。基本和floyd一个思路。

 1 /* 1474 */
 2 #include <cstdio>
 3 #include <cstring>
 4 #include <cstdlib>
 5 
 6 #define MAXN 15
 7 #define MAXK 1005
 8 #define MAXD 35
 9 #define INF    999999
10 
11 int dp[MAXN][MAXK];
12 int day[MAXN][MAXD];
13 int price[MAXN][MAXN][MAXD];
14 
15 int min(int a, int b) {
16     return a<b ? a:b;
17 }
18 
19 int main() {
20     int i, j, k, p;
21     int n, m, d;
22     int t = 0;
23     
24     #ifndef ONLINE_JUDGE
25         freopen("data.in", "r", stdin);
26     #endif
27     
28     while (scanf("%d %d", &n, &m)!=EOF && (n||m)) {
29         for (i=1; i<=n; ++i) {
30             for (j=1; j<=n; ++j) {
31                 if (i == j)
32                     continue;
33                 scanf("%d", &day[i][j]);
34                 for (k=1; k<=day[i][j]; ++k)
35                     scanf("%d", &price[i][j][k]);
36             }
37         }
38         
39         for (i=1; i<=n; ++i)
40             for (j=0; j<=m; ++j)
41                 dp[i][j] = INF;
42         
43         dp[1][0] = 0;
44         for (k=1; k<=m; ++k) {
45             for (i=1; i<=n; ++i) {
46                 for (j=1; j<=n; ++j) {
47                     if (i == j)
48                         continue;
49                     d = (k-1)%day[j][i] + 1;
50                     if (price[j][i][d] && dp[j][k-1]!=INF)
51                         dp[i][k] = min(dp[i][k], dp[j][k-1]+price[j][i][d]);
52                 }
53             }
54         }
55         
56         printf("Scenario #%d\n", ++t);
57         if (dp[n][m] == INF)
58             printf("No flight possible.\n\n");
59         else
60             printf("The best flight costs %d.\n\n", dp[n][m]);
61     }
62     
63     return 0;
64 }

 

posted on 2015-01-16 21:26  Bombe  阅读(161)  评论(0)  编辑  收藏  举报

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