【HDOJ】1057 A New Growth Industry

纯粹的模拟题目。

 1 #include <cstdio>
 2 #include <cstring>
 3 #include <cstdlib>
 4 
 5 #define MAXN 20
 6 #define MAXM 16
 7 
 8 char tb[] = ".!X#";
 9 int D[MAXM];
10 int map[2][MAXN+2][MAXN+1];
11 int dir[4][2] = {
12     {-1,0}, {1,0}, {0,1}, {0,-1}
13 };
14 
15 int isInvalid(int x, int y) {
16     return x<0 || x>=MAXN || y<0 || y>=MAXN;
17 }
18 
19 int main() {
20     int t, n;
21     int i, j, k, p, r;
22     int x, y;
23     int sum;
24 
25 #ifndef ONLINE_JUDGE
26     freopen("data.in", "r", stdin);
27     freopen("data.out", "w", stdout);
28 #endif
29     memset(map , 0, sizeof(map));
30     scanf("%d", &t);
31     while (t--) {
32         scanf("%d", &n);
33         for (i=0; i<MAXM; ++i)
34             scanf("%d", &D[i]);
35         for (r=0, i=1; i<=MAXN; ++i) {
36             for (j=1; j<=MAXN; ++j) {
37                 scanf("%d", &map[r][i][j]);
38             }
39         }
40         for (p=0; p<n; ++p, r=!r) {
41             for (i=1; i<=MAXN; ++i) {
42                 for (j=1; j<=MAXN; ++j) {
43                     sum = map[r][i][j] + map[r][i+1][j] + map[r][i-1][j]+\
44                             map[r][i][j+1] + map[r][i][j-1];
45                     map[!r][i][j] = map[r][i][j] + D[sum];
46                     if (map[!r][i][j] > 3)
47                         map[!r][i][j] = 3;
48                     if (map[!r][i][j] < 0)
49                         map[!r][i][j] = 0;
50                 }
51             }
52         }
53         for (i=1; i<=MAXN; ++i) {
54             for (j=1; j<=MAXN; ++j) {
55                 printf("%c", tb[map[r][i][j]]);
56             }
57             printf("\n");
58         }
59         if (t)
60             printf("\n");
61     }
62 
63     return 0;
64 }

 

posted on 2014-12-12 23:10  Bombe  阅读(187)  评论(0编辑  收藏  举报

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