【HDOJ】2707 Steganography
简单字符串，读懂题，很容易AC。
1 #include <stdio.h> 2 #include <string.h> 3 4 char buf[350], line[85], des[70]; 5 6 int main() { 7 int i, k, tmp, len; 8 int ib, id; 9 10 memset(buf, 0, sizeof(buf)); 11 ib = 0; 12 13 while (gets(line) != NULL) { 14 len = strlen(line); 15 if (len==1 && line[0]=='#') 16 break; 17 if (len==1 && line[0]=='*') { 18 id = 0; 19 for (i=0; i<ib; i+=5) { 20 tmp = (buf[i]<<4) + (buf[i+1]<<3) + (buf[i+2]<<2) + (buf[i+3]<<1) + (buf[i+4]); 21 if (tmp == 0) 22 des[id] = ' '; 23 else if (tmp == 27) 24 des[id] = '\''; 25 else if (tmp == 28) 26 des[id] = ','; 27 else if (tmp == 29) 28 des[id] = '-'; 29 else if (tmp == 30) 30 des[id] = '.'; 31 else if (tmp == 31) 32 des[id] = '?'; 33 else 34 des[id] = tmp-1+'A'; 35 ++id; 36 } 37 des[id] = '\0'; 38 printf("%s\n", des); 39 ib = 0; 40 memset(buf, 0, sizeof(buf)); 41 } else { 42 k = 0; 43 for (i=0; i<len; ++i) { 44 if (k && line[i]!=' ') { 45 buf[ib++] = !(k&1); 46 k = 0; 47 } else if (line[i] == ' '){ 48 ++k; 49 } 50 } 51 } 52 } 53 54 return 0; 55 }
