【HDOJ】2103 Family planning

题目挺有意思。虽然不是很难。

 1 #include <stdio.h>
 2 
 3 int main() {
 4     unsigned int m, n, case_n;
 5     unsigned int i, j, k, tmp, one=1;
 6 
 7     scanf("%u", &case_n);
 8 
 9     while (case_n--) {
10         scanf("%u %u", &m, &n);
11         k = j = 0;
12         for (i=1; i<=n; ++i) {
13             scanf("%u", &tmp);
14             if (tmp && !j)
15                 j = i;
16         }
17         if ( (m==n) && (j==0 || j==n) ) {
18                 printf("0 RMB\n");
19                 continue;
20         }
21         if (j && j<n)
22             tmp = (one<<(n-j))-1;
23         else
24             tmp = 0;
25         if (m<n)
26             k = (one<<(n-m))-1;
27         else
28             k = 0;
29         tmp = (tmp>k) ? tmp:k;
30         if (tmp)
31             printf("%u0000 RMB\n", tmp);
32         else
33             printf("0 RMB\n");
34     }
35 
36     return 0;
37 }

 

posted on 2014-04-20 14:27  Bombe  阅读(227)  评论(0)  编辑  收藏  举报

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