303. Range Sum Query - Immutable

Given an integer array nums, find the sum of the elements between indices i and j (i ≤ j), inclusive.

Example:

Given nums = [-2, 0, 3, -5, 2, -1]

sumRange(0, 2) -> 1
sumRange(2, 5) -> -1
sumRange(0, 5) -> -3

 

Note:

  1. You may assume that the array does not change.
  2. There are many calls to sumRange function
class NumArray(object):

    def __init__(self, nums):
        """
        :type nums: List[int]
        """
        n = len(nums)
        self.np = [0] * (n+1)
        for i in range(n):
            self.np[i+1] = self.np[i] + nums[i]

    def sumRange(self, i, j):
        """
        :type i: int
        :type j: int
        :rtype: int
        """
        return self.np[j+1] - self.np[i]


# Your NumArray object will be instantiated and called as such:
# obj = NumArray(nums)
# param_1 = obj.sumRange(i,j)

 

posted @ 2020-03-17 15:37  米开朗菠萝  阅读(80)  评论(0编辑  收藏  举报