HDU 2859 Phalanx DP
题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=2859
题目大意:求一个矩阵的按反对角线对称的子矩阵的行最大值。
解题思路:dp[i][j]:=以(i,j)为左下角起点的满足条件的矩阵的行最大值,那么将第一行和最后一列初始化为1之后从第0行第n-1列倒着初始化即可。
代码:
1 const int maxn = 1e3 + 100; 2 int n; 3 char maze[maxn][maxn]; 4 int dp[maxn][maxn]; 5 6 void init(){ 7 memset(dp, 0, sizeof(dp)); 8 for(int i = 0; i < n; i++){ 9 dp[0][i] = 1; 10 dp[i][n - 1] = 1; 11 } 12 } 13 void solve(){ 14 int ans = 1; 15 for(int i = 1; i < n; i++){ 16 for(int j = n - 2; j >= 0; j--){ 17 int tmp = dp[i - 1][j + 1], cnt = 1; 18 for(int k = 1; k <= tmp; k++) 19 if(maze[i - k][j] == maze[i][j + k]) cnt++; 20 else break; 21 dp[i][j] = cnt; 22 ans = max(ans, dp[i][j]); 23 } 24 } 25 printf("%d\n", ans); 26 } 27 28 int main(){ 29 while(scanf("%d", &n) && n){ 30 for(int i = 0; i < n; i++) 31 scanf("%s", maze[i]); 32 init(); 33 solve(); 34 } 35 }
题目:
Phalanx
Time Limit: 10000/5000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)
Total Submission(s): 1988 Accepted Submission(s): 988
Problem Description
Today is army day, but the servicemen are busy with the phalanx for the celebration of the 60th anniversary of the PRC.
A phalanx is a matrix of size n*n, each element is a character (a~z or A~Z), standing for the military branch of the servicemen on that position.
For some special requirement it has to find out the size of the max symmetrical sub-array. And with no doubt, the Central Military Committee gave this task to ALPCs.
A symmetrical matrix is such a matrix that it is symmetrical by the “left-down to right-up” line. The element on the corresponding place should be the same. For example, here is a 3*3 symmetrical matrix:
cbx
cpb
zcc
A phalanx is a matrix of size n*n, each element is a character (a~z or A~Z), standing for the military branch of the servicemen on that position.
For some special requirement it has to find out the size of the max symmetrical sub-array. And with no doubt, the Central Military Committee gave this task to ALPCs.
A symmetrical matrix is such a matrix that it is symmetrical by the “left-down to right-up” line. The element on the corresponding place should be the same. For example, here is a 3*3 symmetrical matrix:
cbx
cpb
zcc
Input
There are several test cases in the input file. Each case starts with an integer n (0<n<=1000), followed by n lines which has n character. There won’t be any blank spaces between characters or the end of line. The input file is ended with a 0.
Output
Each test case output one line, the size of the maximum symmetrical sub- matrix.
Sample Input
3
abx
cyb
zca
4
zaba
cbab
abbc
cacq
0
Sample Output
3
3
Source