HDU 1012 u Calculate e

该题只要注意前面几个精度就可以。

#include<stdio.h>
#include<stdlib.h>
int main()
{
    int n=1,a[10]={1};
    while( n<10 )
    {
     a[n]=a[n-1]*n;
     n++;
     }
    printf( "n e\n" );
    printf( "- -----------\n" );
    printf( "0 1\n" );
    printf( "1 2\n" );
    printf( "2 2.5\n" );
    n=3;
    double t=2.5;  
    while( n<10 )
    {
           t+=1.0/a[n];
           printf( "%d %.9lf\n",n,t ); 
           n++;  
    }
   // system( "pause" );
    return 0;    
}