PAT_A1155#Heap Paths
Source:
PAT A1155 Heap Paths (30 分)
Description:
In computer science, a heap is a specialized tree-based data structure that satisfies the heap property: if P is a parent node of C, then the key (the value) of P is either greater than or equal to (in a max heap) or less than or equal to (in a min heap) the key of C. A common implementation of a heap is the binary heap, in which the tree is a complete binary tree. (Quoted from Wikipedia at https://en.wikipedia.org/wiki/Heap_(data_structure))
One thing for sure is that all the keys along any path from the root to a leaf in a max/min heap must be in non-increasing/non-decreasing order.
Your job is to check every path in a given complete binary tree, in order to tell if it is a heap or not.
Input Specification:
Each input file contains one test case. For each case, the first line gives a positive integer N (1), the number of keys in the tree. Then the next line contains N distinct integer keys (all in the range of int), which gives the level order traversal sequence of a complete binary tree.
Output Specification:
For each given tree, first print all the paths from the root to the leaves. Each path occupies a line, with all the numbers separated by a space, and no extra space at the beginning or the end of the line. The paths must be printed in the following order: for each node in the tree, all the paths in its right subtree must be printed before those in its left subtree.
Finally print in a line
Max Heap
if it is a max heap, orMin Heap
for a min heap, orNot Heap
if it is not a heap at all.
Sample Input 1:
8 98 72 86 60 65 12 23 50
Sample Output 1:
98 86 23 98 86 12 98 72 65 98 72 60 50 Max Heap
Sample Input 2:
8 8 38 25 58 52 82 70 60
Sample Output 2:
8 25 70 8 25 82 8 38 52 8 38 58 60 Min Heap
Sample Input 3:
8 10 28 15 12 34 9 8 56
Sample Output 3:
10 15 8 10 15 9 10 28 34 10 28 12 56 Not Heap
Keys:
- 堆(Heap);
- 完全二叉树(Complete Binary Tree);
- 深度优先搜索(Depth First Search);
Attention:
- 完全二叉树采用静态存储,CBTree[1...n],从2/n+1开始为叶子结点;
- 采用RNL遍历
Code:
1 /* 2 Data: 2019-08-03 19:57:18 3 Problem: PAT_A1155#Heap Paths 4 AC: 33:40 5 6 题目大意: 7 层次遍历给出一棵完全二叉树, 8 输出根结点到各个叶子结点的路径,并判断是否为堆 9 输出顺序:从最右叶子到最左叶子 10 基本思路: 11 根右左的顺序遍历二叉树并存储路径,到达叶子结点时打印路径 12 若父亲大于孩子,则非小根堆; 13 若父亲小于孩子,则非大根堆; 14 */ 15 #include<cstdio> 16 #include<vector> 17 using namespace std; 18 const int M=1e3+10; 19 int n,heap[M],Max=1,Min=1; 20 vector<int> path; 21 22 void Travel(int root) 23 { 24 if(root > n) 25 return; 26 path.push_back(heap[root]); 27 if(root!=1 && heap[root]>heap[root/2]) 28 Max=0; 29 if(root!=1 && heap[root]<heap[root/2]) 30 Min=0; 31 if(root > n/2) 32 for(int i=0; i<path.size(); i++) 33 printf("%d%c", path[i], i==path.size()-1?'\n':' '); 34 Travel(root*2+1); 35 Travel(root*2); 36 path.pop_back(); 37 } 38 39 int main() 40 { 41 #ifdef ONLINE_JUDGE 42 #else 43 freopen("Test.txt", "r", stdin); 44 #endif // ONLINE_JUDGE 45 46 scanf("%d", &n); 47 for(int i=1; i<=n; i++) 48 scanf("%d", &heap[i]); 49 Travel(1); 50 if(Max) printf("Max Heap"); 51 else if(Min) printf("Min Heap"); 52 else printf("Not Heap"); 53 54 return 0; 55 }