摘要: 使用快慢指针,如果有环快慢指针一定会相遇 class Solution {public: bool hasCycle(ListNode *head) { ListNode *fast, *slow; fast = slow = head; while(slow && fast) { slow = s 阅读全文
posted @ 2017-10-13 21:34 bloomingFlower 阅读(189) 评论(0) 推荐(0) 编辑