2017.7.12

给一个n位字符串，按顺序从1开始到最大N输出，

bool increment(char *num) {
bool overflow = false;
int jw = 0;//进位否
int n = strlen(num);
for(int i = n - 1; i >= 0; --i) {
int nsum = num[i] - '0' + jw;
if(i = n - 1)
++nsum;
if(nsum >= 10) {
if(i == 0)
overflow = true;
else {
jw = 1;
nsum -= 10;
num[i] = '0' + nsum;
}
}
else {
num[i] = '0' + nsum;
break;
}
}
return overflow;
};