字符串及其操作,字符的Unicode编码

a='a'
b="I'm"
c='''good boy'''

print(b+a+'\\'+c*3)


stuNum = '201909090030'
print('年级是:'+stuNum[0:4])
print('专业编号是:'+stuNum[4:9])
print('序号是:'+stuNum[-3:])\

 

凯撒密码

plainText = input('message:')
for c in plainText:
    print(chr(ord(c)+3),end='')

星座

print(chr(9800))
for i in range(12):
    print(9800+i,chr(9800+i))

 

posted @ 2018-05-21 16:55  12z  阅读(148)  评论(0编辑  收藏  举报