Codeforces Round #754 (Div. 2) C. Dominant Character
如代码,一共有七种情况,注意不要漏掉 "accabba" , "abbacca" 两种情况;
使用find()函数可简化代码,使用方法如下
代码:
#include <iostream> using namespace std; typedef long long ll; int main() { ios::sync_with_stdio(false); cin.tie(0); cout.tie(0); ll T; cin >> T; while (T--) { ll n, ans = -1; string s; cin >> n >> s; if (s.find("accabba") != s.npos) ans = 7; if (s.find("abbacca") != s.npos) ans = 7; if (s.find("acba") != s.npos) ans = 4; if (s.find("abca") != s.npos) ans = 4; if (s.find("aba") != s.npos) ans = 3; if (s.find("aca") != s.npos) ans = 3; if (s.find("aa") != s.npos) ans = 2; cout << ans << endl; } return 0; }