获取JObject的Key值

            JObject jo = (JObject)JsonConvert.DeserializeObject(sent);
            List<string> ls = new List<string>();
            foreach(var item in jo)
            {
                ls.Add(item.Key);
            }

posted @ 2020-08-24 17:51  棂信  阅读(3166)  评论(0编辑  收藏  举报