摘要：
#includeint main(void){ double n,y; printf("Enter n:"); scanf_s("%lf",&n); if(n50){ y=n*0.58; } printf("f(%.2f)=%.2f\n",n,y); return 0;} 阅读全文
摘要：
#includeint main(void){ double num1,num2; char op; printf("Type in an expression:"); scanf("%lf%c%lf",&num1,&op,&num2); if(op=='+') printf("=%.2f\n",num1+num2); else if(op=='-') printf("=%.2f\n",num1-num2); else if(op=='*') 阅读全文