习题2

#include<stdio.h>
int main(void)
{
    double n,y;

    printf("Enter n:");
    scanf_s("%lf",&n);

    if(n<=50){
        y=n*0.53;
    }
    else if(n>50){
        y=n*0.58;
    }
    printf("f(%.2f)=%.2f\n",n,y);

    return 0;
}

posted @ 2013-10-15 17:02  部落波萝  阅读(107)  评论(0编辑  收藏  举报