组合数据类型练习，英文词频统计实例上

1.

>>> dic={}>>> dic['01']='59'
>>> dic['02']='59.1'
>>> dic['03']='59.2'
>>> dic['04']='59.3'
>>> dic['05']='60'
>>> dic
{'01': '59', '02': '59.1', '03': '59.2', '04': '59.3', '05': '60'}
>>> dic['06']='59.5'
>>> dic
{'01': '59', '02': '59.1', '03': '59.2', '04': '59.3', '05': '60', '06': '59.5'}
>>> dic.pop('01')
'59'
>>> dic['02']=61
>>> dic
{'02': 61, '03': '59.2', '04': '59.3', '05': '60', '06': '59.5'}
>>> dic.get('06')
'59.5'
>>> dic.keys()
dict_keys(['02', '03', '04', '05', '06'])
>>> dic.values()
dict_values([61, '59.2', '59.3', '60', '59.5'])

2.

>>> names=['Rose','Wade','Paul','James','Kobe']
>>> scores=[1,3,13,23,24]
>>> ns=dict(zip(names,scores))
>>> ns
{'Rose': 1, 'Wade': 3, 'Paul': 13, 'James': 23, 'Kobe': 24}
>>> s=set(names)
>>> s
{'Kobe', 'Rose', 'Paul', 'Wade', 'James'}
>>> s.add('Bosh')
>>> s
{'Kobe', 'Rose', 'Paul', 'Wade', 'James', 'Bosh'}
>>> s.remove('Bosh')
>>> s
{'Kobe', 'Rose', 'Paul', 'Wade', 'James'}
>>> ss=set('323211123321')
>>> ss
{'3', '2', '1'}
>>> sss=s|ss
>>> sss
{'Kobe', '1', '2', 'Wade', 'James', '3', 'Rose', 'Paul'}
>>> s&ss
set()
>>> sss-s
{'1', '2', '3'}
>>> ls=list('321321321321321321')
>>> ls
['3', '2', '1', '3', '2', '1', '3', '2', '1', '3', '2', '1', '3', '2', '1', '3', '2', '1']
>>> tu.tuple('3213211321')
Traceback (most recent call last):
  File "<pyshell#37>", line 1, in <module>
    tu.tuple('3213211321')
NameError: name 'tu' is not defined
>>> tu=tuple('3212113')
>>> tu
('3', '2', '1', '2', '1', '1', '3')
>>> se=set('32112133')
>>> se
{'3', '2', '1'}
>>> 
>>> for i in ls:
    print(i)

    
3
2
1
3
2
1
3
2
1
3
2
1
3
2
1
3
2
1
>>> for i in ns:
    print(i)

    
Rose
Wade
Paul
James
Kobe
>>> for i in ns:
    print(i,ns[i])

    
Rose 1
Wade 3
Paul 13
James 23
Kobe 24