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首先先看如下例子
Java代码 复制代码 收藏代码
  1. private static class BarWorker implements Runnable {
  2. private static boolean exists = false;
  3. private String name;
  4. public BarWorker(String name) {
  5. this.name = name;
  6. }
  7. public void run() {
  8. if (!exists) {
  9. exists = true;
  10. System.out.println(name + " enter");
  11. System.out.println(name + " working");
  12. System.out.println(name + " leave");
  13. exists = false;
  14. } else {
  15. System.out.println(name + " give up");
  16. }
  17. }
  18. }

static变量exists用来实现同一时间只有一个worker在工作. 但是假设exists的判断和exists = true;之间有了
其他指令呢
Java代码 复制代码 收藏代码
  1. private static class BarWorker implements Runnable {
  2. private static boolean exists = false;
  3. private String name;
  4. public BarWorker(String name) {
  5. this.name = name;
  6. }
  7. public void run() {
  8. if (!exists) {
  9. try {
  10. TimeUnit.SECONDS.sleep(1);
  11. } catch (InterruptedException e1) {
  12. // do nothing
  13. }
  14. exists = true;
  15. System.out.println(name + " enter");
  16. try {
  17. System.out.println(name + " working");
  18. TimeUnit.SECONDS.sleep(2);
  19. } catch (InterruptedException e) {
  20. // do nothing
  21. }
  22. System.out.println(name + " leave");
  23. exists = false;
  24. } else {
  25. System.out.println(name + " give up");
  26. }
  27. }
  28. }

这时输出是
bar2 enter
bar2 working
bar1 enter
bar1 working
bar1 leave
bar2 leave
看到两个线程同时工作了.
这时可以用AtomicBoolean
Java代码 复制代码 收藏代码
  1. private static class BarWorker implements Runnable {
  2. private static AtomicBoolean exists = new AtomicBoolean(false);
  3. private String name;
  4. public BarWorker(String name) {
  5. this.name = name;
  6. }
  7. public void run() {
  8. if (exists.compareAndSet(false, true)) {
  9. System.out.println(name + " enter");
  10. try {
  11. System.out.println(name + " working");
  12. TimeUnit.SECONDS.sleep(2);
  13. } catch (InterruptedException e) {
  14. // do nothing
  15. }
  16. System.out.println(name + " leave");
  17. exists.set(false);
  18. }else{
  19. System.out.println(name + " give up");
  20. }
  21. }
  22. }

因为它提供了原子性操作,其中exists.compareAndSet(false, true)这个操作把比较和赋值操作组成了一个原子操作,
中间不会提供可乘之机.输出为
bar1 enter
bar1 working
bar2 give up 
posted on 2013-02-10 19:13  点石互动  阅读(335)  评论(0编辑  收藏  举报