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Time Limit: 1000MS | Memory Limit: 10000K | |
Total Submissions: 33281 | Accepted: 14836 |
Description
Standard web browsers contain features to move backward and forward among the pages recently visited. One way to implement these features is to use two stacks to keep track of the pages that can be reached by moving backward and forward. In this problem, you are asked to implement this.
The following commands need to be supported:
BACK: Push the current page on the top of the forward stack. Pop the page from the top of the backward stack, making it the new current page. If the backward stack is empty, the command is ignored.
FORWARD: Push the current page on the top of the backward stack. Pop the page from the top of the forward stack, making it the new current page. If the forward stack is empty, the command is ignored.
VISIT : Push the current page on the top of the backward stack, and make the URL specified the new current page. The forward stack is emptied.
QUIT: Quit the browser.
Assume that the browser initially loads the web page at the URL http://www.acm.org/
The following commands need to be supported:
BACK: Push the current page on the top of the forward stack. Pop the page from the top of the backward stack, making it the new current page. If the backward stack is empty, the command is ignored.
FORWARD: Push the current page on the top of the backward stack. Pop the page from the top of the forward stack, making it the new current page. If the forward stack is empty, the command is ignored.
VISIT : Push the current page on the top of the backward stack, and make the URL specified the new current page. The forward stack is emptied.
QUIT: Quit the browser.
Assume that the browser initially loads the web page at the URL http://www.acm.org/
Input
Input
is a sequence of commands. The command keywords BACK, FORWARD, VISIT,
and QUIT are all in uppercase. URLs have no whitespace and have at most
70 characters. You may assume that no problem instance requires more
than 100 elements in each stack at any time. The end of input is
indicated by the QUIT command.
Output
For
each command other than QUIT, print the URL of the current page after
the command is executed if the command is not ignored. Otherwise, print
"Ignored". The output for each command should be printed on its own
line. No output is produced for the QUIT command.
Sample Input
VISIT http://acm.ashland.edu/ VISIT http://acm.baylor.edu/acmicpc/ BACK BACK BACK FORWARD VISIT http://www.ibm.com/ BACK BACK FORWARD FORWARD FORWARD QUIT
Sample Output
http://acm.ashland.edu/ http://acm.baylor.edu/acmicpc/ http://acm.ashland.edu/ http://www.acm.org/ Ignored http://acm.ashland.edu/ http://www.ibm.com/ http://acm.ashland.edu/ http://www.acm.org/ http://acm.ashland.edu/ http://www.ibm.com/ Ignored
Source
分析: 水题,题目怎么说就怎么做。
1 #include <stdio.h> 2 #include <string.h> 3 4 #define MAX_NUM 100 5 6 int main() 7 { 8 char input[MAX_NUM]; 9 char now[MAX_NUM] = "http://www.acm.org/"; 10 char stackForward[MAX_NUM][MAX_NUM]; 11 char stackBack[MAX_NUM][MAX_NUM]; 12 int stackF = 0; 13 int stackB = 0; 14 15 memset(stackForward, 0, MAX_NUM * MAX_NUM * sizeof(char)); 16 memset(stackBack, 0, MAX_NUM * MAX_NUM * sizeof(char)); 17 18 while(1) 19 { 20 scanf(" %s",input); 21 if(strcmp(input, "VISIT") == 0) 22 { 23 stackF = 0; 24 strcpy(stackBack[stackB++], now); 25 scanf(" %s", now); 26 } 27 else if(strcmp(input, "BACK") == 0) 28 { 29 if(stackB == 0) 30 { 31 printf("Ignored\n"); 32 continue; 33 } 34 strcpy(stackForward[stackF++], now); 35 strcpy(now, stackBack[--stackB]); 36 } 37 else if(strcmp(input, "FORWARD") == 0) 38 { 39 if(stackF == 0) 40 { 41 printf("Ignored\n"); 42 continue; 43 } 44 strcpy(stackBack[stackB++], now); 45 strcpy(now, stackForward[--stackF]); 46 } 47 else if(strcmp(input, "QUIT") == 0) 48 { 49 break; 50 } 51 printf("%s\n", now); 52 } 53 54 return 0; 55 }