LeetCode Path Sum

Given a binary tree and a sum, determine if the tree has a root-to-leaf path such that adding up all the values along the path equals the given sum.

For example:
Given the below binary tree and sum = 22,

              5
             / \
            4   8
           /   / \
          11  13  4
         /  \      \
        7    2      1

return true, as there exist a root-to-leaf path 5->4->11->2 which sum is 22.

 

 1 /**
 2  * Definition for binary tree
 3  * public class TreeNode {
 4  *     int val;
 5  *     TreeNode left;
 6  *     TreeNode right;
 7  *     TreeNode(int x) { val = x; }
 8  * }
 9  */
10 public class Solution {
11     public boolean hasPathSum(TreeNode root, int sum) {
12         if (root == null) {
13             return false;
14         }
15         if (root.val==sum && root.left==null && root.right==null) {
16             return true;
17         }
18         
19         return hasPathSum(root.left, sum-root.val) || hasPathSum(root.right, sum-root.val);
20     }
21 }

 

posted @ 2014-10-20 22:25  birdhack  阅读(98)  评论(0)  编辑  收藏  举报