LeetCode Unique Binary Search Trees

Given n, how many structurally unique BST's (binary search trees) that store values 1...n?

For example,
Given n = 3, there are a total of 5 unique BST's.

   1         3     3      2      1
    \       /     /      / \      \
     3     2     1      1   3      2
    /     /       \                 \
   2     1         2                 3


n个点中每个点都可以作为root,当 i 作为root时,小于 i  的点都只能放在其左子树中,大于 i 的点只能放在右子树中,此时只需求出左、右子树各有多少种,二者相乘即为以 i 作为root时BST的总数。

 1 public class Solution {
 2     public int numTrees(int n) {
 3             int[] a=new int[n+1];
 4             a[0]=1;
 5         for (int i = 1; i <= n; i++) {
 6             if (i<3) {
 7                 a[i]=i;
 8             }else {
 9                 for (int j = 1; j <=i; j++) {
10                     a[i]=a[i]+a[j-1]*a[i-j];
11                 }
12             }
13         }
14         return a[n];
15     }
16 }

 

posted @ 2014-09-16 21:48  birdhack  阅读(129)  评论(0编辑  收藏  举报