BZOJ 4821 (luogu 3707)(全网最简洁的代码实现之一)
题面
分析
计算的部分其他博客已经写的很清楚了,本博客主要提供一个简洁的实现方法
尤其是pushdown函数写得很简洁
代码
#include<iostream>
#include<cstdio>
#include<cstring>
#include<algorithm>
#define maxn 100005
using namespace std;
int n,m;
double x[maxn];
double y[maxn];
double get_sumx(double l,double r) {//返回l+(l+1)+...+r
return (l+r)*(r-l+1)/2;
}
double get_sumsqx(double l,double r) {//返回l^2+(l+1)^2+...+r^2
return r*(r+1)*(2*r+1)/6-(l-1)*l*(2*l-1)/6;
}
struct segment_tree {
#define lson pos<<1//宏,简化代码
#define rson pos<<1|1
struct node {
int l;//记录区间端点,方便在计算中调用
int r;
double sx;
double sy;
double sqx;
double xy;
double addx;
double addy;
double len() {//返回区间长度,同样是方便计算
return r-l+1;
}
bool set;
} tree[maxn<<2];
void push_up(int pos) {
tree[pos].sx=tree[lson].sx+tree[rson].sx;
tree[pos].sy=tree[lson].sy+tree[rson].sy;
tree[pos].sqx=tree[lson].sqx+tree[rson].sqx;
tree[pos].xy=tree[lson].xy+tree[rson].xy;
}
void push_down(int pos) {
int son=pos<<1;
if(tree[pos].set) {
for(int i=0; i<=1; i++) {//用循环来遍历,少写一次代码
son=son|i;
tree[son].addx=tree[son].addy=0;
tree[son].sx=tree[son].sy=get_sumx(tree[son].l,tree[son].r);
tree[son].xy=tree[son].sqx=get_sumsqx(tree[son].l,tree[son].r);
tree[son].set=1;
}
tree[pos].set=0;
}
if(tree[pos].addx||tree[pos].addy) {
son=pos<<1;
double mkx=tree[pos].addx;
double mky=tree[pos].addy;
for(int i=0; i<=1; i++) {
son=son|i;
tree[son].addx+=mkx;
tree[son].addy+=mky;
tree[son].sqx+=2*tree[son].sx*mkx+mkx*mkx*tree[son].len();
tree[son].xy+=tree[son].len()*mkx*mky+tree[son].sx*mky+tree[son].sy*mkx;
tree[son].sx+=mkx*tree[son].len();
tree[son].sy+=mky*tree[son].len();
}
tree[pos].addx=tree[pos].addy=0;
}
}
void build(int l,int r,int pos,double *x,double *y) {
tree[pos].l=l;
tree[pos].r=r;
if(l==r) {
tree[pos].sx=x[l];
tree[pos].sy=y[l];
tree[pos].sqx=x[l]*x[l];
tree[pos].xy=x[l]*y[l];
return;
}
int mid=(l+r)>>1;
build(l,mid,pos<<1,x,y);
build(mid+1,r,pos<<1|1,x,y);
push_up(pos);
}
void add_segment(int L,int R,int pos,double s,double t) {
if(L<=tree[pos].l&&R>=tree[pos].r) {
tree[pos].addx+=s;
tree[pos].addy+=t;
tree[pos].xy+=tree[pos].sx*t+tree[pos].sy*s+s*t*tree[pos].len();
tree[pos].sqx+=2*tree[pos].sx*s+s*s*tree[pos].len();
tree[pos].sx+=s*tree[pos].len();
tree[pos].sy+=t*tree[pos].len();
return;
}
push_down(pos);
int mid=(tree[pos].l+tree[pos].r)>>1;
if(L<=mid) add_segment(L,R,pos<<1,s,t);
if(R>mid) add_segment(L,R,pos<<1|1,s,t);
push_up(pos);
}
void set_segment(int L,int R,int pos) {
if(L<=tree[pos].l&&R>=tree[pos].r) {
tree[pos].set=1;
tree[pos].addx=tree[pos].addy=0;
tree[pos].sx=tree[pos].sy=get_sumx(tree[pos].l,tree[pos].r);
tree[pos].sqx=tree[pos].xy=get_sumsqx(tree[pos].l,tree[pos].r);
return;
}
push_down(pos);
int mid=(tree[pos].l+tree[pos].r)>>1;
if(L<=mid) set_segment(L,R,pos<<1);
if(R>mid) set_segment(L,R,pos<<1|1);
push_up(pos);
}
double query_sx(int L,int R,int pos) {
if(L<=tree[pos].l&&R>=tree[pos].r) {
return tree[pos].sx;
}
push_down(pos);
double ans=0;
int mid=(tree[pos].l+tree[pos].r)>>1;
if(L<=mid) ans+=query_sx(L,R,pos<<1);
if(R>mid) ans+=query_sx(L,R,pos<<1|1);
return ans;
}
double query_sy(int L,int R,int pos) {
if(L<=tree[pos].l&&R>=tree[pos].r) {
return tree[pos].sy;
}
push_down(pos);
double ans=0;
int mid=(tree[pos].l+tree[pos].r)>>1;
if(L<=mid) ans+=query_sy(L,R,pos<<1);
if(R>mid) ans+=query_sy(L,R,pos<<1|1);
return ans;
}
double query_sqx(int L,int R,int pos) {
if(L<=tree[pos].l&&R>=tree[pos].r) {
return tree[pos].sqx;
}
push_down(pos);
double ans=0;
int mid=(tree[pos].l+tree[pos].r)>>1;
if(L<=mid) ans+=query_sqx(L,R,pos<<1);
if(R>mid) ans+=query_sqx(L,R,pos<<1|1);
return ans;
}
double query_xy(int L,int R,int pos) {
if(L<=tree[pos].l&&R>=tree[pos].r) {
return tree[pos].xy;
}
push_down(pos);
double ans=0;
int mid=(tree[pos].l+tree[pos].r)>>1;
if(L<=mid) ans+=query_xy(L,R,pos<<1);
if(R>mid) ans+=query_xy(L,R,pos<<1|1);
return ans;
}
#undef lson
#undef rson
} T;
void debug(){
printf("debug:\n");
for(int i=1;i<=n;i++){
printf("%.0f ",T.query_sx(i,i,1));
}
printf("\n");
for(int i=1;i<=n;i++){
printf("%.0f ",T.query_sy(i,i,1));
}
printf("\n");
printf("\n");
}
int main() {
int cmd,l,r;
double s,t;
double up,down,ax,ay;
double sumx,sumy,sumxy,sumsqx;
scanf("%d %d",&n,&m);
for(int i=1; i<=n; i++) {
scanf("%lf",&x[i]);
}
for(int i=1; i<=n; i++) {
scanf("%lf",&y[i]);
}
T.build(1,n,1,x,y);
for(int i=1; i<=m; i++) {
scanf("%d",&cmd);
if(cmd==2) {
scanf("%d %d %lf %lf",&l,&r,&s,&t);
T.add_segment(l,r,1,s,t);
} else if(cmd==3) {
scanf("%d %d %lf %lf",&l,&r,&s,&t);
T.set_segment(l,r,1);
T.add_segment(l,r,1,s,t);
} else {
scanf("%d %d",&l,&r);
sumx=T.query_sx(l,r,1);
sumy=T.query_sy(l,r,1);
sumxy=T.query_xy(l,r,1);
sumsqx=T.query_sqx(l,r,1);
// printf("x=%.0f y=%.0f xy=%.0f x^2=%.0f\n",sumx,sumy,sumxy,sumsqx);
ax=sumx/(r-l+1);
ay=sumy/(r-l+1);
up=ax*ay*(r-l+1)+sumxy-ay*sumx-ax*sumy;
down=sumsqx-2*ax*sumx+(r-l+1)*ax*ax;
printf("%.10f\n",up/down);
}
// debug();
}
}
版权声明:因为我是蒟蒻,所以请大佬和神犇们不要转载(有坑)的文章,并指出问题,谢谢