LuoguP2953 [USACO09OPEN]牛的数字游戏Cow Digit Game(博弈论)

1~9显然,后面平\(A\)过去

#include <iostream>
#include <cstdio>
#include <cstring>
#include <algorithm>
#include <cmath>
#define R(a,b,c) for(register int a = (b); a <= (c); ++a)
#define nR(a,b,c) for(register int a = (b); a >= (c); --a)
#define Fill(a,b) memset(a, b, sizeof(a))
#define Swap(a,b) ((a) ^= (b) ^= (a) ^= (b))

#define ON_DEBUGG

#ifdef ON_DEBUGG

#define D_e_Line printf("-----------\n")
#define D_e(x) std::cout << (#x) << " : " <<x << "\n"
#define FileOpen() freopen("in.txt", "r", stdin)
#define FileSave() freopen("out2.txt", "w", stdout)
#define Pause() system("pause")
#include <ctime>
#define TIME() fprintf(stderr, "\nTIME : %.3lfms\n", clock() * 1000.0 / CLOCKS_PER_SEC)

#else

#define D_e_Line ;
#define D_e(x) ;
#define FileOpen() ;
#define FilSave ;
#define Pause() ;
#define TIME() ;

#endif

struct ios {
	template<typename ATP> ios& operator >> (ATP &x) {
		x = 0; int f = 1; char c;
		for(c = getchar(); c < '0' || c > '9'; c = getchar()) if(c == '-') f = -1;
		while(c >= '0' && c <= '9') x = x * 10 + (c ^ '0'), c = getchar();
		x *= f;
		return *this;
	}
}io;

using namespace std;

template<typename ATP> inline ATP Min(ATP a, ATP b) {
	return a < b ? a : b;
}
template<typename ATP> inline ATP Max(ATP a, ATP b) {
	return a > b ? a : b;
}
template<typename ATP> inline ATP Abs(ATP a) {
	return a < 0 ? -a : a;
}

const int N = 1000007;

int maxx, minn;
inline void Calc(int n) {
	while(n){
		int tmp = n % 10;
		maxx = Max(maxx, tmp);
		if(tmp) minn = Min(minn, tmp);
		n /= 10;
	}
}

int f[N];

int main() {
	R(i,1,9) f[i] = true; 
	R(i,10,N - 5){
		maxx = 0, minn = 10;
		Calc(i);
		if(!(f[i - maxx] && f[i - minn]))
			f[i] = true;
	}
	int Tasks;
	io >> Tasks;
	while(Tasks--){
		int n;
		io >> n;
		if(f[n])
			printf("YES\n");
		else
			printf("NO\n");
	}
	return 0;
}

posted @ 2019-10-20 23:07  邱涵的秘密基地  阅读(120)  评论(0编辑  收藏  举报